Suppose that the new england colonials baseball team is equally likely to win a game as not to win it. if 4 colonials games are
chosen at random, what is the probability that exactly 2 of those games are won by the colonials
1 answer:
1. Consider the tree diagram in the picture attached.
2 Each of the games picked can be a W (win) or a L (lose), the chances are equal
3. All that could happen in 4 picked games is shown in the picture:
2 w 2 l can happen in the following 6 ways: {(W,W,L,L)(W,L,W,L)(W,L,L,W)(L,W,W,L)(L,W,L,W)(L,L,W,W)}
4. P(2W,2L)=6/16=3/8
2 Each of the games picked can be a W (win) or a L (lose), the chances are equal
3. All that could happen in 4 picked games is shown in the picture:
2 w 2 l can happen in the following 6 ways: {(W,W,L,L)(W,L,W,L)(W,L,L,W)(L,W,W,L)(L,W,L,W)(L,L,W,W)}
4. P(2W,2L)=6/16=3/8
You might be interested in
Answer:
Hi there! :)
Recall that the sum of all angles in a triangle = 180°.
Therefore:
34° + 24° + x° = 180°
Combine like terms and subtract:
58° + x° = 180°
x = 180° - 58°
x = 122°