Answer:
There are 1% probability that the last person gets to sit in their assigned seat
Step-by-step explanation:
The probability that the last person gets to sit in their assigned seat, is the same that the probability that not one sit in this seat.
If we use the Combinatorics theory, we know that are 100! possibilities to order the first 99 passenger in the 100 seats.
LIke we one the probability that not one sit in one of the seats, we need the fraction from the total number of possible combinations, of combination that exclude the assigned seat of the last passenger. In other words the amount of combination of 99 passengers in 99 seats: 99!
Now this number of combination of the 99 passenger in the 99 sets, divide for the total number of combination in the 100 setas, is the probability that not one sit in the assigned seat of the last passenger.
P = 99!/100! = 99!/ (100 * 99!) = 1/100
There are 1% probability that the last person gets to sit in their assigned seat
Answer:
x = -11/4
Step-by-step explanation:
Given that:
-2 = 5 / (2x+3)
Multiplying both sides by (2x + 3)
-2(2x + 3) = 5
"-" sign will alter the inner signs
-4x -6 = 5
Adding 6 on both sides:
-4x -6 +6 = 5 + 6
-4x = 11
Dividing both sides by -4
-4x/-4 = 11/-4
x = -11/4
i hope it will help you!
I don't know if that is factor-able. It looks like you could just subtract and get 64t. which would lead to the answer being zero since you divide by zero when isolating the variable t.
Answer:
The graph of the parent function f(x) = |x| is dashed and the graph of the transformed function g(x) = |x| + k is solid. Use the slider to change the value of k. How does changing the value of k affect the graph? Positive values of k shift the graph . Negative values of k shift the graph .
Answer:
D. X= -100
Step-by-step explanation:
5×x/5=5×(-20) (reduce and multiply)
X= -100
