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Oxana [17]
3 years ago
6

Determine the equation of the circle graphed below.

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

=  >  {x}^{2}  +  {y}^{2}  + 6x - 14y + 49 = 0

Step-by-step explanation:

From the graph we can see that

Diameter = 6 units

=> Radius = 3 units and centre is at (-3,7)

=> Equation is Circle with centre (-3,7) and radius of 3 units will be

=  >  {(x + 3)}^{2}  +  {(y - 7)}^{2}  =  {3}^{2}

=  > ( {x}^{2}  + 6x + 9) + ( {y}^{2}  - 14y + 49) = 9

=  >  {x}^{2}  +  {y}^{2}  + 6x - 14y + 49 = 0

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