Question

A spinner used for a game is divided into 3 sections: yellow, green, and orange. Janie spins the spinner 20 times. The spinner lands on green 8 times. What is the experimental probability that the spinner does NOT land on green?

Answer 1

2/3 is the answer. Try not to overthink these answers because they’re usually quite simple in the end. :)

Answer 2

Answer: $\dfrac{3}{5}$

Step-by-step explanation:

Given : A spinner used for a game is divided into 3 sections: yellow, green, and orange.

Janie spins the spinner 20 times.

The spinner lands on green 8 times.

It means , the number of times it does not land on green section = 20-8=12

Then, the experimental probability that the spinner does NOT land on green :-

$\text{P(green)}=\dfrac{\text{Number of times spinner does not land on green}}{\text{Total number of times spinner spins}}\\\\=\dfrac{12}{20}=\dfrac{3}{5}$

∴ Required probability = $\dfrac{3}{5}$