The percentage of this plane that's enclosed by the pentagons is closest to: D. 56.
<h3>How to determine the percentage?</h3>
Since the side of the small square is a, then the area of the tile is
given by:
Area of tiles = 9a²
<u>Note:</u> With an area of 9a², 4a² is covered by squares while 5a² by pentagons.
This ultimately implies that, 5/9 of the tiles are covered by pentagons and this can be expressed as a percentage as follows:
Percent = 5/9 × 100
Percent = 0.555 × 100
Percent = 55.5 ≈ 56%.
Read more on area of square here: brainly.com/question/8902873
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Complete Question:
The plane is tiled by congruent squares of side length a and congruent pentagons of side lengths a and a²/a, as arranged in the diagram below. The percent of the plane that is enclosed by the pentagons is closest to (A) 50 (B) 52 (C) 54 (D) 56 (E) 58
(-2x)(x^2)+(-2x)(-3) = -2x^3 + 6x
0.00373134328
I think you can round that but I think that's the answer.
We can form two ratios to help us solve this:
(2x+6):10 = (x+6):8
(2x+6) (x+6)
--------- = --------
10 8
Cross multiply:
8(2x+6) = 10(x+6)
Foil:
16x + 48 = 10x + 60
Move like variables to the same side:
16x - 10x = 60 - 48
6x = 12
x = 2
Line AE = 2x+6
Plug 2 for x into the equation: 2(2) + 6 = 10
Hope this helps, and May the Force Be With You!
-Jabba