Question

WILL GIVE BRAINLIEST find the minimum value of the parabola y=x^2+42/5

Answer 1

Answer:

Minimum value = $(0, \frac{42}{5} )$

1. Set up the function in general form
2. Determine the direction of the graph
3. Calculate -b/2a
4. Find the corresponding f(x) value
5. Write your quadratic function in standard or vertex form

Please Mark Brainliest If This Helped!