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3 years ago

Evaluate -99 + 3^2•5

Mathematics

1 answer:

aksik [14]3 years ago

7 0

Answer:

= - 54

Step-by-step explanation:

- 99 + 3^2•5

- 99 + 9 × 5

- 99 + 45

= - 54

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In a small town, 60% of the households have a pet dog. If a household has a pet dog, there is a 70% chance that the household al

Marrrta [24]

Using proportions, it is found that there is a 0.54 = 54% probability that a randomly selected household owns a cat.

<h3>What is a proportion?</h3>

A proportion is a fraction of total amount.

In this problem, the proportions associated with owning a cat are given by:

70% of 60%(also have a dog).

30% of 40%(do not have a dog).

Hence:

p = 0.7(0.6) + 0.3(0.4) = 0.42 + 0.12 = 0.54.

0.54 = 54% probability that a randomly selected household owns a cat.

More can be learned about proportions at brainly.com/question/24372153

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3 years ago

A segment has an endpoint at (2, 4) and a midpoint at (4. 2). What are the coordinates of the other endpoint (2, 10) B. (3, 1) C

stiks02 [169]

Answer:

Step-by-step explanation:

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3 years ago

Need help ASAP I need the right answers

Nana76 [90]

1 is A, 2 is B, 4 is C, 5 is B, 6 is C, cant answer 4 bc it’s cut off

3 0

3 years ago

Benjamin writes an expression for the sum of 1 cubed, 2 cubed, and 3 cubed -- What is the value of the expression? options---

saw5 [17]

Answer:

Step-by-step explanation:

1^3 + 2^3 + 3^3= 1+8+27

9+27= 36

7 0

3 years ago

State whether the following coordinates on a Cartesian plane form an acute, obtuse or right triangle: a) (-1, 1), (7,-2) and (1,

LiRa [457]

Answer:

a) Acute triangle

b) Right triangle

Step-by-step explanation:

∵ A triangle having sides a, b and c is called,

Acute : If a² + b² > c² or a² + c² > b² or b² + c² > a²,

Obtuse : if a² + b² < c² or a² + c² < b² or b² + c² < a²

Right : a² + b² = c² or a² + c² = b² or b² + c² = a²,

a) Let A≡(-1, 1), B≡(7,-2) and C≡(1,-5),

By the distance formula,

$AB=\sqrt{(7-(-1))^2+(-2-1)^2}=\sqrt{(7+1)^2+(-3)^2}=\sqrt{8^2+3^2}=\sqrt{64+9}=\sqrt{73}\text{ unit}$

Similarly,

$BC=\sqrt{45}\text{ unit}$

$CA=\sqrt{40}\text{ unit}$

∵ The sum of any two sides is greater than third side,

So, ABC is a triangle,

Now,

$AB^2 + BC^2 > CA^2$

⇒ ABC is an acute triangle.

b) Let P≡(0,6), Q≡(1,2) and R≡(5,3),

By the distance formula,

PQ = √17 unit,

QR = √17 unit,

RP = √34 unit,

∵ The sum of any two sides of PQR is greater than third side,

⇒ PQR is a triangle ,

Also,

$RP^2=PQ^2+QR^2$

Hence, PQR is a right triangle.

3 0

3 years ago