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matrenka [14]
3 years ago
5

The product of two positive consecutive integers is 24 more than 6 times the first number.

Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

The product of two integers is 72.

Step-by-step explanation:

Let,

x and x+1 be the two consecutive positive integers.

According to given statement;

The product of two positive consecutive integers is 24 more than 6 times the first number.

x(x+1) = 6x+24

x^2+x=6x+24\\x^2+x-6x-24=0\\x^2-5x-24=0\\x^2-8x+3x-24=0\\x(x-8)+3(x-8)=0\\(x-8)(x+3)=0\\

Either,

x-8 = 0

x=8

Or,

x+3 = 0

x=-3

As the integer is positive, therefore, the two integers are 8 and 9.

Product of two integers = 8*9 = 72

Hence,

The product of two integers is 72.

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Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

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<h2>Answer:\frac{3}{2}<u><em></em></u></h2>

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Step 2: Add the product from Step 1 (8) to the numerator (4).

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\frac1{4}{8} =\frac{3}{2}

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