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1 year ago

55% of what number is 33?

Mathematics

1 answer:

EastWind [94]1 year ago

4 0

Answer:

18.15

Step-by-step explanation:

55% = 55/100

33 = 33/1

33/1 x 55/100

33 x 55 = 1815

1 x 100 = 100

1815/100 = 18.15

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Information on a packet of seeds, which may not be a random sample of seeds, claims that the germination rate is 94%. What's

Evgesh-ka [11]

Answer:

0.1052

Step-by-step explanation:

Given that proportion of germination in the population is 94% =0.94

p = 0.96

Sample size = 220

Std dev of p = $\sqrt{\frac{pq}{n} } \\=0.016$

The probability that more than 96% of the 220 seeds in the packet will germinate

= $P(p\geq 0.96)\\=P(Z\geq \frac{0.96-0.94}{0.016})\\=P(Z\geq 1.25)\\==1-0.8948\\=0.1052$

Assumptions are np and nq >5 and also sample size >220 hence normal

7 0

2 years ago

Karla has spent $42 on food. She bought

Mandarinka [93]

Answer:

What is the question?

Step-by-step explanation:

4 0

2 years ago

If sales tax is 6% and you buy a shirt for $25 how much do you owe?

Leona [35]

Answer:

26.50

Step-by-step explanation:

First we need to calculate the sales tax

25 * 6%

Changing to decimal from

25 * .06

1.50

Then we add the tax to the cost of the shirt

25+1.50

26.50

We owe 26.50

7 0

2 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

2 years ago

What is the domain of the relation?

Masja [62]

Answer:

the domain of the relation is C

5 0

2 years ago