I answered 2. Am I right?
1 answer:
Answer:
Yes, I agree, the score of 2 was an outlier, outside of what is close to everyone else's score
Step-by-step explanation:
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Hello,
Let x be the number of 14-ounce cans
800-x be the number of bottles
Total weight=14*x+70*(800-x)=14x+56000-70x=56000-56x=56(1000-x)
Answer:
See below for answers and explanations
Step-by-step explanation:
<u>Part A</u>

<u>Part B</u>

<u>Part C</u>

Answer: you got this
Step-by-step explanation:
Answer:
<h2>
231</h2>
Step-by-step explanation:

Substitute values into the given equation
