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1 year ago

Which of the following may fall outside a triangle?

Mathematics

1 answer:

algol [13]1 year ago

7 0

Answer: B

Step-by-step explanation:

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Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form? 5x + 3y = 18 5x – 3y = 30

ddd [48]

$\bf C(\stackrel{x_1}{3}~,~\stackrel{y_1}{-5})\qquad 
D(\stackrel{x_2}{6}~,~\stackrel{y_2}{0})
\\\\\\
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-5)}{6-3}\implies \cfrac{0+5}{6-3}\implies \cfrac{5}{3}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{5}{3}(x-3)\implies y+5=\cfrac{5}{3}(x-3)$

$\bf \stackrel{\textit{multiplying both sides by LCD of 3}}{3(y+5)=3\left[ \cfrac{5}{3}(x-3) \right]}\implies 3y+15=5(x-3)
\\\\\\
3y+15=5x-15\implies -5x+3y=-30\implies \stackrel{\textit{multiplying by -1}}{5x-3y=30}$

bearing in mind the standard form uses all integers, and the x-variable cannot have a negative coefficient.

6 0

3 years ago

Read 2 more answers

When you raise (almost) anything to the power zero, you get 1.

larisa86 [58]

Answer:

z^0= 1

(2v+2)^0 = 1

3^0 = 1

0^0= 0

Step-by-step explanation:

When you raise (almost) anything to the power zero, you get 1 and when you raise 0 to any number except 0 is 0

6 0

1 year ago

Is for over two and 20/6 proportions

ad-work [718]

No they're not proportional, and it's four*.
4/2 = 2
20/6 = 3.333333333334 or 3 1/3

4 0

3 years ago

Read 2 more answers

i need help with this i need the area found on the rectangle but ion know how to find it, plzzzz helpppppp!!!!!!!!!!! oh and ple

Ber [7]

Step-by-step explanation:

Tan30=4/adj

adj Tan 30= 4

adj=4/tan30

adj=6.93m

Area=L×b

4×6.93=27.72m

8 0

3 years ago

Which two values of x are roots of the polynomial below?<br> x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

<u>Solution:</u>

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$

Hence, the roots of given polynomial are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

6 0

3 years ago