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3 years ago

Hyxetdryufgukhchfxrdtygujhftyuhuhyguhjygyu

Mathematics

2 answers:

motikmotik3 years ago

7 0

Yea that is correct. also you should watch attack on titan it’s a pretty good show. also the plot is amazing

nikklg [1K]3 years ago

6 0

Answer:

so the answer is: eijieljnqwsmiqwmx

did i answer it correctly let me know

Step-by-step explanation:

Destroy your keyboard by smashing each random word on the poor broken keyboard

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EThe graph of a quadratic function passes through the points (6,0) and (p,0). The maximum point

MA_775_DIABLO [31]

Answer:

p = - 5

Step-by-step explanation:

The vertex of the function is (0.5, 30.25 )

Since the roots are (6, 0) and (p, 0) then the axis of symmetry is vertical

with equation x = 0.5

The axis of symmetry passes through the midpoint of the roots, thus

$\frac{6+p}{2}$ = 0.5 ( multiply both sides by 2 )

6 + p = 1 ( subtract 6 from both sides )

p = - 5

6 0

3 years ago

Find the sum of the series Summation from n equals 1 to infinity (StartFraction 3 Over StartRoot n plus 2 EndRoot EndFraction mi

Marizza181 [45]

Looks like the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}$

The series telescopes; consider the $k$ th partial sum of the series,

$S_k=\displaystyle\sum_{n=1}^k\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}$

$S_k=\displaystyle\left(\frac3{\sqrt3}-\frac32\right)+\left(\frac32-\frac3{\sqrt5}\right)+\cdots+\left(\frac3{\sqrt{k+1}}-\frac3{\sqrt{k+2}}\right)+\left(\frac3{\sqrt{k+2}}-\frac3{\sqrt{k+3}}\right)$

$\implies S_k=\dfrac3{\sqrt3}-\dfrac3{\sqrt{k+3}}$

As $k\to\infty$ , the second term converges to 0, leaving us with

$\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}=\frac3{\sqrt3}=\boxed{\sqrt3}}$

7 0

3 years ago

Simplify this expression 1x/18x

USPshnik [31]

Wouldn't it be 1/18x?????

7 0

3 years ago

3. How much interest does $5300 earn at a rate of 2.8% interest compounded quarterly after 6

azamat

Answer:

The interest is $I=\$74.46$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=6/12=0.5\ years\\ P=\$5,300\\ r=0.028\\n=4$

substitute in the formula above

$A=5,300(1+\frac{0.028{4})^{4*0.5}$

$A=5,300(1.007)^{2}$

$A=\$5,374.46$

<em>Find the interest</em>

$I=A-P$

substitute

$I=\$5,374.46-\$5,300=\$74.46$

5 0

3 years ago

Plz help I really need it and you get 15 points

Andrei [34K]

1. 1 x-200= -200
2. -200 x 1= -200
3. 2 x -100= -200
4. -100 x 2= -200
5. -20 x 10= -200
6. -10 x 20= -200
7. -40 x 5= -200
8. -5 x 40= -200
Hope this helps! :)

8 0

2 years ago