You must drive more than 40 miles to make option A the cheaper plan
<em><u>Solution:</u></em>
Two payment options to rent a car
Let "x" be the number of miles driven in one day
<em><u>You can pay $20 a day plus 25¢ a mile (Option A)</u></em>
25 cents is equal to 0.25 dollars
OPTION A : 20 + 0.25x
<em><u>You pay $10 a day plus 50¢ a mile (Option B)</u></em>
50 cents equal to 0.50 dollars
Option B: 10 + 0.50x
<em><u>For what amount of daily miles will option A be the cheaper plan ?</u></em>
For option A to be cheaper, Option A must be less than option B
Option A < Option B

Solve the inequality
Add -0.50x on both sides

Add - 20 on both sides,



Divide both sides by 0.25

Thus you must drive more than 40 miles to make option A the cheaper plan
Answer:
Each bag costs $4.75
Step-by-step explanation:
41.22 = 3.22 + 8x
38 = 8x
4.75 = x
Let N be the number of items sold and p the price.
Since the variation is inverse, then the relation between N and p is:

For N=20000 and p = $9.5, we get the formula:

If p = 8.75, then the number of items sold can be computed using the formula:
6 = k/9 => k = 6 x 9 = 54 N
a = 54/2 = 27 meters per second per second