All categories

3 years ago

Is this right? please answer asap

Mathematics

1 answer:

MakcuM [25]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

5.25 is the rate of change/slope

hope this helps :3

if it did pls mark brainliest

You might be interested in

1. At the gym on Monday, Larry is told to up his weight on the bench-press by 15% from last week. Last week he was bench-pressin

QveST [7]

Answer:

300 lbs

Step-by-step explanation:

We know that Larry bench pressed 200 lbs last week, and that he is supposed to increase by 15%. We know that any number times one is that same numbers. That means a number that is increaseing has to be greater than 1. So, we have to convert 15% into a decimal. That is 0.15. That plus one is 1.15. Now we just have to multiply 1.15 with 200. We get 300.

3 0

2 years ago

Find p(-3) and p(5) for the function p(x) = 2x⁴ + 3x³ - 9x² + 16x + 13.

fredd [130]

Answer:

-35, 1493

Step-by-step explanation:

p(x) = 2x⁴ + 3x³ - 9x² + 16x + 13

p(-3) = 2(-3⁴) + 3(-3³) - 9(-3²) + 16(-3) + 13

-3² = 9

-3³ = -27

-3⁴ = 81

p(-3) = 2(81) + 3(-27) -9(9) - 48 + 13

p(-3) = 162 - 81 - 81 -48 + 13

81 + 81 = 162 therefore 162 - 81 - 81 cancels

-48 + 13 = -35

p(5) = 2(5⁴) + 3(5³) - 9(5²) + 16(5) + 13

5² = 25

5³ = 125

5⁴ = 625

p(5) = 2(625) + 3(125) - 9(25) + 80 + 13

p(5) = 1250 + 375 - 225 + 93

p(5) = 1250 + 150 + 93

p(5) = 1493

3 0

2 years ago

Based on the Fundamental Theorem of Algebra, how many complex roots does each of the following equations have? Write your answer

Galina-37 [17]

According to the fundamental theorem of algebra, <span>every polynomial of degree n has n complex zeroes.

Part A:

Given

$x(x^2-4)(x^2+16)=0 \\ \\ \Rightarrow x(x^4+12x^2-64)=0 \\ \\ \Rightarrow x^5+12x^3-64x=0$

Thus, the given polynomial is of degree 5 and hence has 5 omplrex roots.

Part B:

Given

$(x^2+4)(x+5)^2 = 0 \\ \\ \Rightarrow(x^2+4)(x^2+10x+25)=0 \\ \\ \Rightarrow x^4+10x^3+25x^2+4x^2+40x+100=0 \\ \\ \Rightarrow x^4+10x^3+29x^2+40x+100=0$

Thus, the polynomial is of degree 4 and hence has 4 complex roots.

Part C:

Given

$x^6-4x^5-24x^2+10x-3=0$

Thus, the given polynomial is of degree 6 and hence has 6 complex roots.

Part D:

Given

$x^7+128=0$

</span><span>Thus, the given polynomial is of degree 7 and hence has 7 complex roots.</span>

Part E:

Given

$(x^3+9)(x^2-4)=0 \\ \\ \Rightarrow x^5-4x^3+9x^2-36=0$

Thus, the given polynomial is of degree 5 and hence has 5 complex roots.

4 0

3 years ago

Plssssss help meee...

pogonyaev

Answer: PQR=32

Step-by-step explanation:

RQS+PQR=PQS

(4x+4)+(3x-1)=80

7x+3=80

7x=77

x=11

PQR=(3x-1)=> (3(11)-1) => 33-1=32

3 0

3 years ago

Lins smart phone was fully charged when she started school at 8:00 am at 9:20 am it was at 90% charged and at noom it was 72 % c

andriy [413]

Answer:

nzznjznzz

Step-by-step explanation:

ejsdndndnd

5 0

3 years ago