Answer:
The following transcript has been encoded can you decode it???
Explanation:
It is a ceasar cipher. Shift every letter in the alphabet by 22 positions.
The most appropriate answer is C !! software os used for using hardware !!
Answer:
The wireless adapter to use is the Wireless USB 2.0 Extender
Explanation:
The Wireless USB 2.0 Extender is a USB component that enables a computer to connect to and communicate with other computers on a network, or even to connect to the internet.
It uses an IEEE 802.11g radio platform and communicates within a radio frequency range of 2.4GHz.
Therefore, in cases where a notebook computer does not have a built-in wireless LAN card or PC card interface, you can use the Wireless USB 2.0 Extender as the best solution to that problem.
Answer:
The complete Matlab code along with step by step explanation is provided below.
Matlab Code:
function Req=ParallelR(Number)
Number=input('Please enter the number of resistors: ');
if Number>10 | Number<=0
disp('Invalid input')
return
end
R=0;
for i=1:Number
r=input('Please enter the value of resistor: ');
R=R+1/r;
end
Req=1/R;
end
Explanation:
Parallel resistance is given by
First we get the input from the user for how many parallel resistors he want to calculate the resistance.
Then we check whether the user has entered correct number of resistors or not that is from 1 to 10 inclusive.
Then we run a for loop to get the resistance values of individual resistors.
Then we calculated the parallel resistance and keep on adding the resistance for N number of resistors.
Output:
Test 1:
Please enter the number of resistors: 3
Please enter the value of resistor: 10
Please enter the value of resistor: 20
Please enter the value of resistor: 30
ans = 60/11
Test 2:
Please enter the number of resistors: 11
Invalid input
Test 3:
Please enter the number of resistors: 0
Invalid input
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
