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likoan [24]
2 years ago
8

Each month, Margie's pets need 3 bags of dog food and 2 bags of cat food. How many bags of pet food would she need for 4 months?

Which equation shows how to solve this problem?
Mathematics
2 answers:
Serjik [45]2 years ago
8 0

Answer:

12

Step-by-step explanation:

since Margie needs 3 dogs food in a month you multiply 3 by 4 (3x4) and get 12. Another way you could do it is add 3 four times since she needs 3 bags in a month so, 3+3+3+3=12.

Hope it helps:)

natulia [17]2 years ago
5 0

Answer:

20 bags; 3 x 4 + 2 x 4 = <em>y</em> bags of pet food

Step-by-step explanation:

4 x 2 = 8 bags of cat food

4 x 3 = 12 bags of dog food

12 + 8 = 20 bags in total

So, we now know how many bags of pet food Margie needs for 4 months. To write an equation based on this, we need to include how many times Margie would buy each type of pet food. Which, in this case, would be 4 months. So, 4 months times 2 bags of cat food equals 8 bags of cat food, and 4 months times 3 bags of dog food equals 12 bags of dog food. This all together equals <em>y</em> amount of bags for pet food. In conclusion, 3 x 4 + 2 x 4 = <em>y</em> bags of pet food.

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6 0
2 years ago
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A high school coach wants to buy new shirts for the 25 members of the track team. The coach must spend less than $300 on the shi
aksik [14]
25 less than or equal too 300,not really enough information
3 0
3 years ago
What is the simplified for of square root of 100x^36
Slav-nsk [51]

What is the simplified for of square root of

100x^36.

√100 = 10

36 : 2 = 18

10x^18

8 0
4 years ago
The probability is 51​% that the sample mean will be between what two​ values, symmetrically distributed around the population​
Alisiya [41]

Answer:

The lower bound is, -z=-0.69 and the upper bound is z=0.69.

Step-by-step explanation:

Let the random variable <em>X</em> follows a normal distribution with mean <em>μ </em>and standard deviation <em>σ</em>.

The the random variable <em>Z, </em>defined as Z=\frac{X-\mu}{\sigma} is standardized random variable also known as a standard normal random variable. The random variable  Z\sim N(0, 1).

The standard normal random variable has a symmetric distribution.

It is provided that P(-z\leq Z\leq z)=0.51.

Determine the upper and lower bound as follows:

P(-z\leq Z\leq z)=0.51\\P(Z\leq z)-P(Z\leq -z)=0.51\\P(Z\leq z)-[1-P(Z\leq z)]=0.51\\2P(Z\leq z)-1=0.51\\2P(Z\leq z)=1.51\\P(Z\leq z)=0.755

Use a standard normal table to determine the value of <em>z.</em>

The value of <em>z</em> such that P (Z ≤ z) = 0.755 is 0.69.

The lower bound is, -z=-0.69 and the upper bound is z=0.69.

5 0
3 years ago
Fast forward a few years...and suppose you need to get your car repaired. You see the ads above. Your father, who knows a bit ab
katovenus [111]

Mikes repair shop $100 service charge plus $65 per hour Amys auto repair $40 service charge plus $80 per hour write an equation for each repair shop to represent the total cost of a car repair as a function of the number of hours worked let C = total cost to you let h = number of hours worked. Suppose you need to get the dent in your car repaired you see the ads above in the newspaper your father who knows a bit about cars said it would take no more than 3 hours for the repair person to fix your car how do you determine where you should take your car to get it repaired

-Mike Cost:: M(3) = 100 +65*3 = $295

-Amy Cost:: A(3) = 40 + 80*3 = $280

------------------------------------------------------------

-Mike charges 100 dollars service charge plus 65 dollars per hour.

-Amy charges 40 dollars service charge plus 80 dollars per hour.

-The cost to repair from mike is 100 + 65 * x.

-The cost to repair from amy is 40 + 80 * x.

------------------------------------------------------------

Let x = 3 and you get:

The cost to repair from mike is 100 + 65 * 3 = 295 dollars.

The cost to repaid from amy is 40 + 80 * 3 = 280 dollars.

As long as the time to repair is 3 hours or less, the cost to repair will be cheaper from Amy.

8 0
3 years ago
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