Here are the answers you were looking for:
A) Yes
B) No
C) No
<h2><u>Solution</u> :-</h2>
Height of Eric = 6 + 1/6 feet
= 37/6 feet
Height of his brother = 5 + 3/4 feet
= 23/4 feet
Difference between their height :
= 37/6 - 23/4
= (74 - 69)/12
= 5/12
<u>Hence</u>,
Eric is 5/12 feet taller than his brother.
Answer:
2 - 2y^2 - x/y
Step-by-step explanation:
2x^2/x^2 = 2
and
x^2/xy = x/y
therefore
2x^2/x^2 - y^2 - x^2/xy - y^2
= 2 - y^2 - x/y - y^2
= 2 - y^2 - y^2 - x/y
= 2 - 2y^2 - x/y
Answer:
W = 15/4 ft . ib
Step-by-step explanation:
Force = 10ib
According to hooked law, f(x) = kx
x = 4inches = 4/12 ft
x= 1/3ft
f(x) = 1/3k
10 = 1/3k
k = 30 ib/ft
f(x) = 30x
Workdone = integral of f(x) with its limit
6 inches = 6/12 ft
= 1/2ft
W = integral(1/2 to 0) of 30x
W = 15x^2(1/2 to 0)
W = 15(1/2)^2 - 15(0)^2
W = 15(1/4) - 0
W = 15/4 ft. Ib
Answer:
KL = 50
Step-by-step explanation:
∆JML is similar to ∆JNL. it follows that:
[tex] \frac{JM}{JN} = \frac{JL}{JK} [\tex]
JM = 4 + 20 = 24
JN = 4
JL = 10 + KL
JK = 10
Plug in the values
[tex] \frac{24}{4} = \frac{10 + KL}{10} [\tex]
[tex] 6 = \frac{10 + KL}{10} [\tex]
Multiply both sides by 10
[tex] 6*10 = \frac{10 + KL}{10}*10 [\tex]
[tex] 60 = 10 + KL [\tex]
Subtract 10 from each side
[tex] 60 - 10 = KL [\tex]
[tex] 50 = KL [\tex]
KL = 50
