![\bf \begin{array}{rllll} (6&,&3)&f(x)\\ x&&y\\\\ (-\frac{1}{2}x&,&3)&f(-\frac{1}{2}x)\\\\ (-\frac{1}{2}\cdot 6&,&3)\\\\ (-3&,&3) \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Brllll%7D%0A%286%26%2C%263%29%26f%28x%29%5C%5C%0Ax%26%26y%5C%5C%5C%5C%0A%28-%5Cfrac%7B1%7D%7B2%7Dx%26%2C%263%29%26f%28-%5Cfrac%7B1%7D%7B2%7Dx%29%5C%5C%5C%5C%0A%28-%5Cfrac%7B1%7D%7B2%7D%5Ccdot%206%26%2C%263%29%5C%5C%5C%5C%0A%28-3%26%2C%263%29%0A%5Cend%7Barray%7D)
keep in mind that, a negative coefficient to "x", will make the graph reflect over the y-axis.
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Answer:
0
Step-by-step explanation:
The function is defined everywhere except at x=-6. The limit value is the function value at that point.
f(6) = (6^2 -36)/(6 +6) = 0/12 = 0
The limit of the function is 0 as x → 6.
Answer:
first put the numbers on the lines then plot the points that are given
Step-by-step explanation:
first with the numbers of the line then plot the points that are given and you will find the slope and y-intercept of the equation