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Zinaida [17]
2 years ago
9

Regress smoker on cubic polynomials of age, using a linear probability model. What is the p-value for testing the hypothesis tha

t the probability model is linear in age? (two decimal places)
Mathematics
1 answer:
Vlada [557]2 years ago
8 0

The statement " only the estimate intercept is statistically significant at the 5% level is wrong" is wrong about the estimate.

<h3>What is probit regression?</h3>

A probit model is a type of regression in statistics where the dependant variable can only take two values.

We have:

Regress smoker on cubic polynomials of age

If we use linear probability model.

Here the data are missing, but we can say about the estimate that:

Only the estimate intercept is statistically significant at the 5% level is wrong,

Thus, the statement " only the estimate intercept is statistically significant at the 5% level is wrong" is wrong about the estimate.

Learn more about the probit regression here:

brainly.com/question/23389011

#SPJ4

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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
Two cars leave a town at the same time heading in opposite directions. One car is traveling 12 mph faster than the other. After
Katena32 [7]
<span>Find the speed of each car.
Let a be the first car
Let b be the second car
=> a = x miles per hour
=> b = x + 12 miles per hour
=> 2 (x+ x + 12) = 232 miles per hour
=> 2x + 12 = 232
=> 2x + 12 = 116
=> 2x = 116 - 12
=> 2x / 2 = 104 / 2
=> x = 52 (speed of Car A)
=> 52 + 12 = 64 miles per hour (speed of Car B)</span>



4 0
3 years ago
When solving the equation such as 2/3x = 4/5 , why would you multiply both sides of the equation by the reciprocal of 2/3 ?
barxatty [35]
Answer: Well you’re solving for “x,” so you’ll need to isolate this variable. This means we need to “get rid of” the fraction 2/3 that is attached to it. The faction is attached by the operation multiplication, so to remove it we must divide it on both sides. And division with fractions requires the reciprocal. (Try watching an explanation if you’re confused on why division requires reciprocals).
7 0
3 years ago
Four times a difference of 17 and a number is 84.
hichkok12 [17]
4×17-x=84
68-x=84
-x=16
x=-16
5 0
3 years ago
Anybody know this answe cause I don’t
wariber [46]

Answer:

1.875 Pounds

Step-by-step explanation:

8 0
3 years ago
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