Answer:
We validate that the formula to determine the translation of the point to its image will be:
A (x, y) → A' (x+4, y-1)
Step-by-step explanation:
Given
A (−1, 4)→ A' (3, 3)
Here:
- A(-1, 4) is the original point
- A'(3, 3) is the image of A
We need to determine which translation operation brings the coordinates of the image A'(3, 3).
If we closely observe the coordinates of the image A' (3, 3), it is clear the image coordinates can be determined by adding 4 units to the x-coordinate and subtracting 1 unit to the y-coordinate.
Thue, the rule of the translation will be:
A(x, y) → A' (x+4, y-1)
Let us check whether this translation rule validates the image coordinates.
A (x, y) → A' (x+4, y-1)
Given that A(-1, 4), so
A (-1, 4) → A' (-1+4, 4-1) = A' (3, 3)
Therefore, we validate that the formula to determine the translation of the point to its image will be:
A (x, y) → A' (x+4, y-1)
Answer:
x is 3.4 i think
Step-by-step explanation:
Answer:
D.
Step-by-step explanation:
Complementary angles are two angles whose measures add to 90°.
A.
m<CFD = 150° - 100° = 50°
m<EFD = 180° - 150° = 30°
Sum = 80°
No
B.
m<AFB = 40°
m<DFE = m<EFD = 30°
Sum = 70°
No
C.
m<AFC = 100°
Sum > 100°
No
D.
m<BFC = 100° - 40° = 60°
m<DFE = 30°
Sum = 90°
Yes
Answer: D.
Answer:
(f • g)(3) = 100, the distance in miles the bus traveled
Step-by-step explanation:
The product of (miles/hour) and (hours) is (miles), so only answers with units of distance are applicable. The numbers are ...
f(3) = 2·3² +2 = 20 . . . . miles per hour
g(3) = 3+2 = 5 . . . . hours
so (f·g)(3) = f(3)·g(3) = 20·5 = 100 . . . . miles
This means only the first answer choice is applicable.
Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
