Two math classes took the same quiz. The scores of 10 randomly selected students from each class are listed below.

Please help me with those question please help with out number 1

alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

------------------------------------------------------------------------------------------

2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

-------------------------------------------------------------------------------------------

3)

x = 0, y = 1

x = 1, y = $\frac{7}{5}$

x = 5, y = 3

x = 10, y = 5

-------------------------------------------------------------------------------------------------

4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

$y=5x+5$

When x = 0, y = ?

$y=5(0)+5\\y=0+5\\y=5$

When x = 1, y = ?

$y=5(1)+5\\y=5+5\\y=10$

When x = 2, y = ?

$y=5(2)+5\\y=10+5\\y=15$

When x = 3, y = ?

$y=5(3)+5\\y=15+5\\y=20$

-------------------------------------------------------------------------------------------------------

2)

$y=5x-2$

When x = 0, y = ?

$y=5(0)-2\\y=0-2\\y=-2$

When x = 2, y = ?

$y=5(2)-2\\y=10-2\\y=8$

When x = 4, y = ?

$y=5(4)-2\\y=20-2\\y=18$

When x = 6, y = ?

$y=5(6)-2\\y=30-2\\y=28$

----------------------------------------------------------------------------------------------------

3)

$y=\frac{2}{5}x +1$

When x = 0, y = ?

$y=\frac{2}{5}(0) +1$

$y=0 +1\\y=1$

When x = 1, y = ?

$y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1$

$y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5} \\y=\frac{7}{5}$

When x = 5, y = ?

$y=\frac{2}{5}(5) +1\\y=2+1\\y=3$

When x = 10, y = ?

$y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5$

-------------------------------------------------------------------------------------------------

4)

$y=15x+2$

When x = 0, y = ?

$y=15(0)+2\\y=0+2\\y=2$

When x = 1, y = ?

$y=15(1)+2\\y=15+2\\y=17$

When x = 2, y = ?

$y=15(2)+2\\y=30+2\\y=32$

When x = 5, y = ?

$y=15(5)+2\\y=75+2\\y=77$

4 0

3 years ago

Read 2 more answers

What is the value of (2.4 x 10^3)+(5.7×10^2)

nordsb [41]

Answer:

2970

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If ΔABC is an equilateral triangle with, AB = 2x + 17, BC = 6x - 19, AC = 4x-1, find x and the measure of each side

Soloha48 [4]

Answer:

$x=9, AB=BC=AC=35$

Step-by-step explanation:

Equilateral triangles have 3 congruent sides, so all 3 sides have the same length. Therefore, we know that $AB=BC=AC$ . We are given the lengths of all 3 sides in terms of $x$ , but we only need to set two of them equal to each other to solve for $x$ . Let's use $AB$ and $BC$ to solve for $x$ . We know that $AB=BC$ , $AB=2x+17$ , and $BC=6x-19$ . Therefore, we can write the following equation to solve for