The volume of a cone is V=(1/3)(area of the base)(height)= (1/3)(pi*r^2)(h)
r^2= (d/2)^2 = (d^2)/4. Given: V= 301.44cm^3 and h= 18cm.
r^2= V/[(1/3)(pi)(h)]
r^2= 3V/(pi)(h)
(d^2)/4= 3(301.44)/(3.14)(18)
d^2= 12(301.44)/(3.14)(18)
d^2= 63.967
d= 7.997
d~= 8cm.
Answer:
199
Step-by-step explanation:
plug in x=19.6, then
g(19.6) = 10 * 19.6 +3= 199
Answer:
1) y=⅚x -2⅓
2) y=8/3x -5
Step-by-step explanation:
<u>Point-slope form:</u>
y=mx+c, where m is the gradient and c is the y-intercept.
Parallel lines have the same gradient.
Gradient of given line= 
Thus, m=⅚
Susbt. m=⅚ into the equation,
y= ⅚x +c
Since the line passes through the point (4, 1), (4, 1) must satisfy the equation. Thus, substitute (4, 1) into the equation to find c.
When x=4, y=1,
1= ⅚(4) +c

Thus the equation of the line is
.
The gradients of perpendicular lines= -1.
Gradient of given line= -⅜
-⅜(gradient of line)= -1
gradient of line
= -1 ÷ (-⅜)
= -1 ×(-8/3)
= 

When x=3, y=3,

Thus the equation of the line is
.
1. 208/x = 100/130
2. multiply both sides by x
3. 208 = 0.76923x
4. divide both sides by 0.76923
5. x = 270.4