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lbvjy [14]
3 years ago
9

How to do this question? Please tell me the answer with steps

Mathematics
2 answers:
ololo11 [35]3 years ago
3 0

\dfrac{2\cos \theta \sin \theta}{\tan(90-\theta)}=2\sin^2 \theta\\\\
\dfrac{2\cos \theta \sin \theta}{\cot \theta}=2\sin^2 \theta\\\\
\dfrac{2\cos \theta \sin \theta}{\dfrac{\cos \theta}{\sin \theta}}=2\sin^2 \theta\\\\
2\cos \theta \sin \theta\cdot\dfrac{\sin \theta}{\cos \theta}=2\sin^2 \theta\\\\
2\sin^2 \theta=2\sin^2 \theta

Pavel [41]3 years ago
3 0

Consider a right angled triangle with hypotenuse c and legs  a and b. Let sin theta =  a/c .

Then cos theta =  b/c  and  tan (90-theta) = b/a

Then  2 sin theta cos theta /  tan (90 - theta)

= 2 * a/c * b/c  /  b/a

= 2 *  ab/c^2 * a/b

= 2 a^2 /  c^2   = 2 sin^2 theta

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while shopping for clothes, Tracey spent 38$ less than 3 times what Daniel spent. write and solve an equation to find how much D
alexandr1967 [171]

\bold{\huge{\orange{\underline{Solution}}}}

\bold{\underline{ Given :- }}

  • <u>While </u><u>shopping </u><u>for </u><u>clothes </u><u>Tracey </u><u>spent </u><u>3</u><u>8</u><u>$</u><u> </u><u>less </u><u>than </u><u>3</u><u> </u><u>times </u><u>of </u><u>what </u><u>Daniel </u><u>spent </u>

\bold{\underline{ To\: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>determine </u><u>the </u><u>total </u><u>cost </u><u>spent </u><u>by </u><u>daniel</u>

\bold{\underline{ Let's \: Begin :- }}

Cost spent by Tracey for her clothes = 38$

Let assume the spending by Daniel is x

\bold{\underline{Therefore ,}}

\sf{ x / 3 = 38 }

\sf{ x  = 38 × 3 }

\sf{ x = 114 dollar }

\sf{\red{ Hence,\: Daniel\: spent\: 114 \: dollars\: on \: His\: clothes }}

7 0
3 years ago
Find the values of m and b that make the following function differentiable.
Sonbull [250]
The derivative of f(x) at x=3 is 2x=6 approaching from the left side (apply power rule to y=x^2). The derivative of f(x) at x=3 is m approaching from the right side. In order for the function to be differentiable, the limit of derivative at x=3 must be the same approaching from both sides, so m=6. Then, x^2=mx+b at x=3, plug in m=6, 9=18+b, so b=-9.
7 0
3 years ago
Read 2 more answers
In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p
skelet666 [1.2K]

Answer:

\mathbf{P(X=5) =0.0888}    

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

\mathtt{P(X=x) =(^{n}_{x} )   \  \pi^x \  (1-\pi)^{n-x}}

\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} )   \  \pi^x \  (1-\pi)^{n-x}}

where;

n = 8 and π = 0.36

For x = 5

The probability \mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} )   \  0.36^5 \  (1-0.36)^{8-5}}

\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} )   \  0.36^5 \  (0.64)^{3}}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =({8 \times 7 } )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =0.0887645}

\mathbf{P(X=5) =0.0888}     to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5)\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})

{P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times  (0.36)^0  \times  (1-0.36)^8  \ )  +  \dfrac{8!}{1!(7!)} \times  (0.36)^1  \times  (1-0.36)^7  \ +\dfrac{8!}{2!(6!)} \times  (0.36)^2  \times  (1-0.36)^6  \ +  \dfrac{8!}{3!(5!)} \times  (0.36)^3  \times  (1-0.36)^5 +  \dfrac{8!}{4!(4!)} \times  (0.36)^4  \times  (1-0.36)^4  \  +  \dfrac{8!}{5!(3!)} \times  (0.36)^5  \times  (1-0.36)^3  \ )

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1  - P( x  ≤ 5 )

P ( x ≥ 6) = 1  - 0.9707

P ( x ≥ 6) = 0.0293

4 0
3 years ago
The perimeter of a triangle is 105. the lengths of all three sides are represented by three consecutive odd integers. Find the l
aev [14]
The longest side of the triangle is 37.
8 0
3 years ago
Find the solution to the following: *
Trava [24]

Answer:

First one: x = all real numbers

Second one: x = 0

Step-by-step explanation:

for the first one

given 8x+10=2(4x+5) we need to isolate the variable (x) using inverse operations

step 1 distribute the 2 to what is in the parenthesis ( 4x and 5 )

2 * 4x = 8x

5 * 2 = 10

now we have 8x + 10 = 8x + 10

step 2 subtract 8x from each side

8x - 8x = 0

8x - 8x = 0

now we have 10 = 10

subtract 10 from each side

10 - 10 = 0

10 - 10 = 0

we're left with 0 = 0 meaning that all real numbers are solutions

For the second one

given 3x-8=2(x-4) once again we need to isolate the variable using inverse operations

step 1 distribute the 2 to what is in the parenthesis (x - 4)

2 *x = 2x

2 * -4 = -8

now we have 3x - 8 = 2x - 8

step 2 add 8 to each side

-8 + 8 = 0

-8 + 8 = 0

now we have 2x = 3x

step 3 subtract 2x from each side

3x - 2x = x

2x - 2x = 0

we're left with x = 0

5 0
3 years ago
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