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Radda [10]
3 years ago
15

Suppose x is any positive number. Circle 1 has a center at (−2, 7) and a radius of 8x. Circle 2 has a center at (−3, 0) and a ra

dius of 5x. Why is Circle 1 similar to Circle 2?Circle 1 and Circle 2 have the same area, and Circle 1 has a radius 0.625 times longer than Circle 2.Circle 1 is a translation of 1 unit right and 7 units up from Circle 2, and a dilation of Circle 2 with a scale factor of 1.6.Circle 1 is a translation of 1 unit right and 7 units up from Circle 2, and a dilation of Circle 2 with a scale factor of 0.625.Circle 1 and Circle 2 have the same circumference, and Circle 1 has a radius 1.6 times the length of Circle 2's radius.
Mathematics
1 answer:
Virty [35]3 years ago
6 0

Answer:

The correct answer is "Circle 1 is a translation of 1 unit right and 7 units up from Circle 2, and a dilation of Circle 2 with a scale factor of 1.6"

Step-by-step explanation:

We can tell this because first they identify the movement properly. When going from (-3, 0) to (-2, 7), we move to the right one and up 7.

Also, we know there is a scale factor of 1.6, because when we look at the radius of each circle, we can divide and find that factor.

8x/5x = 1.6

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Step-by-step explanation:

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<u>Asymptote</u>: a line that the curve gets infinitely close to, but never touches.

As the degrees of the numerator and denominator of the given function are equal, there is a horizontal asymptote at  y=\dfrac{a}{b}  (where a is the leading coefficient of the numerator, and b is the leading coefficient of the denominator).  This is the end behavior.

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