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kvasek [131]
2 years ago
5

HELP MY QUICKLY PLEASE PLEASE find the equation of the line. use exact numbers.

Mathematics
2 answers:
zalisa [80]2 years ago
8 0

Answer:

we can’t see correctly

take another screen shot and ask the question again

Andru [333]2 years ago
3 0

Answer:

y = 4x - 9

or y = 4x + -9

Step-by-step explanation:

First, you must find a point that intersects with the line

The point that intersects the line is: (3,3)

Second, you must do rise over run, to find out how far one point is from the other

Rise over run consists of the rise (the change in y, going up or down) divided by the run (the change in x, going from left to the right).

So, for this question, the slope would be up 4 and to the left 1 or 4/1 = 4

Then we must find the y-int

The y-int is the number that intersects the y-int

So, for this question it would be -9

You can't see the whole graph in the picture, but you can kind of see it intersect the number -9

So, we must put together the equation, which is y = mx + b

m = slope = 4

b = y-int = -9

So, the equation would be: y = 4x - 9 or y = 4x + -9

here is a graph with the equation

and another graph with rise over run

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Eliminate the parameter,t, in the parametric equation, x=6cos t, and y =3 sin t
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X = 6 cos(t) 
y = 3 sin(t)

we can rewrite these equations as:

\frac{x}{6}=cost(t) \\ \\ \frac{y}{3} =sin(t)

Taking squares of both equations we get:

( \frac{x}{6})^{2}=sin^{2} (t) \\  \\ 
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Adding both the equations, we get:

\frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=sin^{2}(t)+cos^{2}(t)   \\  \\ 
 \frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=1
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6 0
3 years ago
What values of b satisfy 3(2b + 3)2 = 36?
KiRa [710]

the correct question is

What values of b satisfy 3(2b+3)^2 = 36


we have

3(2b+3)^2 = 36

Divide both sides by 3

(2b+3)^2 = 12

take the square root of both sides

( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3


b1=\frac{\sqrt{12}}{2} -\frac{3}{2}

b1=\sqrt{3} -\frac{3}{2}


b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}

therefore


the answer is

the values of b are

b1=\sqrt{3} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}


6 0
2 years ago
Read 2 more answers
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