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3 years ago

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.

Mathematics

1 answer:

Sedbober [7]3 years ago

8 0

Answer:

The weight : 9 pound

Lamar would pay for his dinner : $71

Step-by-step explanation:

Let x represent the weight of the lobster

the cost of the dinner at restaurant 1 is 4x + 35

the cost of the dinner at restaurant 2 is 3x + 44

Now ,we have to solve the equation :

4x + 35 = 3x + 44

-3x - 35 -3x - 35 -> trying to get all x terms on one side. other just #

4x - 3x = 44 - 35

⇔ 1x = 9

⇔ x = 9

In this case Lamar would pay the same amount for his dinner at any restaurant:

the price = 4×(9)+35 = 71

= 3×(9)+44 = 71.

Hope this helps, Let me know if you have any question/concerns !

Have a nice rest of your day :)

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-8p=40 Solve for P (Algebra)

STALIN [3.7K]

Step-by-step explanation:

solution

or,-8p=40

or, p=40/-8

or, p=-5

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3 years ago

Anyone know how to do these?

erastovalidia [21]

Answer:

B. 1/m¹⁸

Step-by-step explanation:

To simplify the equation, we start with the values inside the brackets.

Therefore m⁻¹m⁵ results to m⁴.

This is because the sign between the m⁻¹ and m⁵ is multiplication, and when multiplying figures that have a similar base, we add the indices.

that is, -1+5=4

then we divide m⁴ by m⁻², that is, m⁴/m⁻²=m⁶

To divide figures that have the same base we subtract the powers.

That is, 4-(-2)=6

the resulting expression from inside the brackets will be (m⁶)³ which results to m⁻¹⁸ which is the same as 1/m¹⁸

3 0

3 years ago

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What is the volume of a cube with a side length of 3t5units? Cube V = s3

ikadub [295]

Answer:

V=a3=33=27

Step-by-step explanation:

sorry if its wrong

8 0

3 years ago

Please help! Will mark the brainliest!

JulsSmile [24]

The domain is the set of all possible x-values which will make the function valid.
$f(x) = \frac{6}{x+3} \ \ \ \ , \ g(x) = \frac{1}{4-x}$
For the given function The denominator of a fraction cannot be zero

(a)

(1) The domain of f ⇒⇒⇒ R - {-3}

Because ⇒⇒⇒ x+3 = 0 ⇒⇒⇒ x =-3

(2) The domain of g ⇒⇒⇒ R - {4}
Because: 4 - x = 0 ⇒⇒⇒ x = 4

(3) $f + g = \frac{6}{x+3} + \frac{1}{4-x} = \frac{6(4-x)+(x+3)}{(x+3)(4-x)}$
The domain of (f+g) ⇒⇒⇒ R - {-3,4}
because: x+3 = 0 ⇒⇒⇒ x = -3   and    4 - x = 0 ⇒⇒⇒ x = 4

(4) $f - g = \frac{6}{x+3} - \frac{1}{4-x} = \frac{6(4-x)-(x+3)}{(x+3)(4-x)}$
The domain of (f-g) ⇒⇒⇒ R - {-3,4}
because: x+3 = 0 ⇒⇒⇒ x = -3   and    4 - x = 0 ⇒⇒⇒ x = 4

(5) $f * g = \frac{6}{x+3} * \frac{1}{4-x} = \frac{6}{(x+3)(4-x)}$
The domain of (f*g) ⇒⇒⇒ R - {-3,4}
because: x+3 = 0 ⇒⇒⇒ x = -3   and    4 - x = 0 ⇒⇒⇒ x = 4

(6) $f * f = \frac{6}{x+3} * \frac{6}{x+3} = \frac{36}{(x+3)^2}$
The domain of ff ⇒⇒⇒ R - {-3}

Because ⇒⇒⇒ x+3 = 0 ⇒⇒⇒ x =-3

(7) $\frac{f}{g} = \frac{\frac{6}{x+3} }{ \frac{1}{4-x} } = \frac{6(4-x)}{x+3}$
The domain of (f/g) ⇒⇒⇒ R - {-3,4}

because: x+3 = 0 ⇒⇒⇒ x = -3   and    4 - x = 0 ⇒⇒⇒ x = 4
(8) $\frac{g}{f} = \frac{ \frac{1}{4-x} }{ \frac{6}{x+3} } = \frac{x+3}{6(4-x)}$
The domain of (g/f) ⇒⇒⇒ R - {-3,4}

because: x+3 = 0 ⇒⇒⇒ x = -3   and    4 - x = 0 ⇒⇒⇒ x = 4
===================================================
(b)

(9) $(f+g)(x) = \frac{6}{x+3} + \frac{1}{4-x} = \frac{6(4-x)+(x+3)}{(x+3)(4-x)}$

∴ $(f + g)(x) = \frac{24-6x+x+3}{(x+3)(4-x)} = \frac{27-5x}{(x+3)(4-x)}$

(10) $(f - g)(x) = \frac{6}{x+3} - \frac{1}{4-x} = \frac{6(4-x)-(x+3)}{(x+3)(4-x)}$

∴ $(f - g)(x) = \frac{24-6x-x-3}{(x+3)(4-x)} = \frac{21 - 7x}{(x+3)(4-x)}$

(11) $(f * g)(x) = \frac{6}{x+3} * \frac{1}{4-x} = \frac{6}{(x+3)(4-x)}$

(12) $(f * f)(x) = \frac{6}{x+3} * \frac{6}{x+3} = \frac{36}{(x+3)^2}$

(13) $(\frac{f}{g})(x) = \frac{\frac{6}{x+3} }{ \frac{1}{4-x} } = \frac{6(4-x)}{x+3}$

(14) $(\frac{g}{f})(x) = \frac{ \frac{1}{4-x} }{ \frac{6}{x+3} } = \frac{x+3}{6(4-x)}$

===================================================

7 0

3 years ago

FOR BRAINLIEST Express 0.64 as a fraction in lowest terms. 5/32 64/10 16/25 4/5

Nadusha1986 [10]

Answer:In its decimal form, it says ' 64 / 100 '.

In order to change it to its lowest terms, we look to see whether the

numerator and denominator have a common factor greater than ' 1 '.

If they do, then we can divide numerator and denominator by their

common factor, and have the same fraction in lower terms.

The common factors of 64 and 100 are 1, 2, and 4 .

We could divide top and bottom by 2, but that wouldn't finish the job.

It's always best to divide them by their greatest common factor, and

once you do that, you're done.

Dividing the numerator and denominator both by 4,

we get the fraction in its lowest terms:

0.64 = 64/100 = 16/25

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers