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3 years ago

FOR BRAINLIEST Express 0.64 as a fraction in lowest terms. 5/32 64/10 16/25 4/5

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

7 0

Answer:In its decimal form, it says ' 64 / 100 '.

In order to change it to its lowest terms, we look to see whether the

numerator and denominator have a common factor greater than ' 1 '.

If they do, then we can divide numerator and denominator by their

common factor, and have the same fraction in lower terms.

The common factors of 64 and 100 are 1, 2, and 4 .

We could divide top and bottom by 2, but that wouldn't finish the job.

It's always best to divide them by their greatest common factor, and

once you do that, you're done.

Dividing the numerator and denominator both by 4,

we get the fraction in its lowest terms:

0.64 = 64/100 = 16/25

Step-by-step explanation:

Serjik [45]3 years ago

3 0

Answer:

Step-by-step explanation:

its b it cant be further simplified.

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7 0

2 years ago

spin [16.1K]

Answer:

$z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67$

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=18 represent the ounce cups of coffee that were underfilled

$\hat p=\frac{18}{100}=0.18$ estimated proportion of ounce cups of coffee that were underfilled

$p_o=0.1$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion it's higher than 0.1 or 10%:

Null hypothesis: $p\leq 0.1$

Alternative hypothesis: $p > 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed for this case is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a one right tailed test the p value would be:

$p_v =P(Z>2.67)=0.0037$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance thetrue proportion is not significanlty higher than 0.1 or 10% .