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ehidna [41]
3 years ago
9

the members of the boosters organization at your high school bought new balls for the school. they spent $22.00 per basketball a

nd $30.00 per football, spending a total of $648.00. They bought 6 more footballs than basketballs. How many of each type of ball did they buy?
Mathematics
1 answer:
BabaBlast [244]3 years ago
5 0

Answer:

Number of basketball = 9

Number of football = 15


Step-by-step explanation:

let number of basketball = x

let number of football = y


Given that cost of 1 basketball = 22

Then cost of x basketball = 22x


Given that cost of 1 football = 30

Then cost of x football = 30y


Then total expense = 22x+30y

Given total expense is $648 so we can set both equal to each other and get:

22x+30y=648...(i)


Given that they bought 6 more footballs than basketballs

so we get:

y=6+x...(ii)


Now plug (ii) into (i)

22x+30y=648

22x+30(6+x)=648

22x+180+30x=648

52x+180=648

52x=648-180

52x=468

x=9

plug x=9 into (ii)

y=6+x=6+9=15

Hence final answer is :

Number of basketball = 9

Number of football = 15


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Step-by-step explanation:

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Answer:

m∠R=76°

Step-by-step explanation:

∠STR=∠RST=(2x+2)° (base angles of isos triangle)

2(2x+2)+(3x+1)=180 (angle sum of triangle)

      4x+4+3x+1=180

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Read 2 more answers
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