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cupoosta [38]
3 years ago
9

Find the perimeter of the polygon with the vertices U(−2, 4), V(3, 4),U(−2, 4), V(3, 4), and W(3,−4)W(3,−4).

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
4 0

Answer:

Perimeter = 22.434

Step-by-step explanation:

To find the perimeter we need to find the length of all three sides, and we do that by finding the distance between the points that form the sides:

The formula for the distance between two points is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

side UV:

UV = \sqrt{(-2 - 3)^2 + (4 - 4)^2}  = 5

side VW:

VW = \sqrt{(3 - 3)^2 + (4 - (-4))^2}  = 8

side UW:

UW = \sqrt{(-2 - 3)^2 + (4 - (-4))^2}  = 9.434

So the perimeter is:

P = UV + VW + UW

P = 5 + 8 + 9.434 = 22.434

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Genrish500 [490]
A. x intercepts are where the graph hits the x axis or where f(x)=0
0=2x^2-x-10
solve
hmm
we can use the ac method
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what 2 numbers muliply to get -20 and add to get -1 (the coefint of the x term)
-5 and 4
split the midd into that
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group
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factor
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undistribute
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f(x)=2x^2-x-10
2>0
opoens up
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ok, the vertex

the x value of  the vertex in f(x)=ax^2+bx+c= is -b/(2a)
the y value of the vertex is f(-b/(2a)) so
given
f(x)=2x^2-x-10
a=2
b=-1
-b/2a=-(-1)/(2*2)=1/4
f(1/4)=2(1/4)^2-(1/4)-10
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f(1/4)=1/8-1/4-10
f(1/4)=1/8-2/8-80/8
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C. graph the x intercepts and the vertex
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