All categories

2 years ago

A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/2. What is the y-intercept of the function?

1 answer:

5 0

Based on the calculations, we can logically deduce that the y-intercept of this sine function is equal to: A. 3.

<u>Given the following data:</u>

Amplitude = 3

Period = π

Phase shift = π/2

<h3>How to determine the y-intercept of this function?</h3>

Mathematically, a sine function is modeled by this equation:

y = Asin(ωt + ø)

<u>Where:</u>

A represents the amplitude.

ω represents angular velocity.

t represents the period.

ø represents the phase shift.

Also, the period of a sine wave is given by:

t = 2π/ω

2 = 2π/ω

ω = 2

Substituting the given parameters into the equation, we have;

y = 3sin(2t + π/2)

At t = 0, we have:

y = 3sin(2(0) + π/2)

y = 3sin(π/2)

y = 3sin(90)

y = 3 × 1

y = 3.

In conclusion, we can logically deduce that the y-intercept of this sine function is equal to 3.

Read more on phase shift here: brainly.com/question/27692212

#SPJ1

You might be interested in

If Luke pushes his sister in a wagon down the driveway that is 14 meters long and it takes 22 Newtons of force, how much work di

erica [24]

Hello!

The answer is:

Luke did a work of 308N.m or 308 Joules.

When a force is applied on a object making it to move covering a distance we call it "work". The movement caused by the force, will follow the same direction that the force.

We can calculate the work done by using the following equation:

$Work=Force*distance*Cos(\alpha)$

Where,

Work is the transferred energy.

Force, is the force applied to the object.

Distance, is the distance covered due to the applied force.

α, is the angle at the work is done.

We are given the following information to calculate the work done:

$Force=22N\\Distance=14m$

So, substituting the given information into the equation to calculate work, we have:

$Work=Force*distance\\Work=22N*14m=308N.m$

Hence, we have that Luke did a work of 308N.m or 308 Jouls.

Have a nice day!

3 0

4 years ago

F = 0.27<br>100 f = (0.27)(100)<br>100 f = ?

Sholpan [36]

100 f= 27

(0.27)*100=27

3 0

3 years ago

Read 2 more answers

Find the value of x when a⊥b and b||c.

dem82 [27]

Answer: 8

Step-by-step explanation: Because a is perpendicular to b, the value of 9x + 18 = 90. If we subtract 18 from both sides, it becomes 9x = 72. Divide by 9 on both sides to get 8

6 0

3 years ago

( x, y) satisfies both equations y+18=x(x-3) and x=y+6

antoniya [11.8K]

Answer:

(- 2, - 8 ) , (6, 0 )

Step-by-step explanation:

y + 18 = x(x - 3) ← distribute

y + 18 = x² - 3x → (1)

x = y + 6 → (2)

Substitute x = y + 6 into (1)

y + 18 =(y + 6)² - 3(y + 6) ← expand parenthesis using FOIL

y + 18 = y² + 12y + 36 - 3y - 18

y + 18 = y² + 9y + 18 ( subtract y + 18 from both sides )

0 = y² + 8y = y(y + 8)

Equate each factor to zero and solve for y

y = 0

y + 8 = 0 ⇒ y = - 8

Substitute these values into (2) and evaluate for x

y = 0 : x = 0 + 6 = 6 ⇒ (6, 0 )

y = - 8 : x = - 8 + 6 = - 2 ⇒ (- 2, - 8 )

3 0

3 years ago

For what fraction of a day will a 12-hour digital clock that shows only the hours and minutes display at least one 5 or 6

Brums [2.3K]

Answer: 4/9

Step-by-step explanation:

Find out combinations without 5 or 6.

Minutes with 5 or 6: 05,06,15,16,25,26,35,36,45,46,50–59. It 10+10=20 minutes per hour. And 40 minutes without 5 or 6.

Hours with 5 or 6: 5 and 6. Without 5 and 6 is 0,1,2,3,4,7,8,9,10,11 (10 hours).

Total time without 5 and 6 is 10*40minutes=400 minutes.

Time with 5 or 6 is 12*60–400=320 minutes.

Fraction of a day: 320/(12*60)=4/9=0.44444

7 0

3 years ago