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2 years ago

2. You want to buy some beans. A

Mathematics

1 answer:

Ber [7]2 years ago

4 0

Answer:

Step-by-step explanation:

Remark

If you find out the cost of 1 oz of each of them, that will determine the best buy. The smallest number is the best buy.

Givens

7 oz cost $2.38

15 oz cost $5.25

26 oz cost $8.58

Solution

7 oz cost $2.38

1 oz cost x This is a proportion. 3 quatities are known. Find x Cross multiply.

7/1 = 2.38/x

7x = 2.38

x = $0.34 dollars

15 oz cost 5.25

1 oz costs x

15.1/1 = 5,25 x Cross Multiply

15x = 5.25 * 1 Divide by 15

x = 5.25 / 15

x = $0.35

26 oz cost 8.58

1 oz cost x

26/1 = 8.38/x Cross Multiply

26x = 8.38 Divide by 26

x = 8.38/20

x = 0.32 dollars

Answer

7 oz cost 0.34

15 oz cost 0.35

26 oz cost 0.32

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2 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

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Answer:

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Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

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First, convert the given time to minutes

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$Security\ A = 2\ mins+ 20\ secs$

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$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

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