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lana [24]
2 years ago
5

Two mechanics worked on a car. The first mechanic worked for 5 hours, and the second mechanic worked for 15 hours. Together they

charged a total of $1950. What was the rate charged per hour by each mechanic if the sum of the two rates was $200 per hour?
Mathematics
1 answer:
Wewaii [24]2 years ago
3 0
X = rate of mechanic who worked 5 hours

y = rate of mechanic who worked 15 hours

x + y = 200
5x + 15y = 1950

you find the first variable in one of the equations, then subsitute the result into the other equation. your answer would be:

the mechanic who worked for 5 hours charged $105 per hour, the one who worked 15 hours charged $95 per hour.

hope this helps :)


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Alexandra has some dimes and some quarters. She has no more than 21 coins worth a minimum of $3.75 combined. If Alexandra has 4
olga55 [171]

Answer:

A minimum of 10 dimes and 11 quarters is what Alexandra will have

Step-by-step explanation:

Let

d = number of dimes

q = number of quarters

Since she has 21 coins altogether,

d + q = 21------------------------equation 1    

  •  If these coins are worth $3.75 then

0.10 x d + 0.25 x q = 3.75

  • which is 0.10d +.25q =3.75 --------------------------equation 2

where $.10 is the value of one dime and $.25 is the value of one quarter

make d the subject of formula from equation 1 d = 21 -q----------equation 3

 insert it in equation 2

0.10d +0.25q =3.75

0.10(21-q) + 0.25q = 3.75

0.1(21)-0.1q+0.25q=3.75

2.1 +0.15q = 3.75

0.15q  = 3.75-2.1 = 1.65

q = 1.65/0.15 =165/15 =11

  • since we have the value of q insert in equation 3

d = 21 - q

d = 21-11

d = 10

Alexandra has 10 dimes and 11 quarters.

from my calculation i can see that the a minimum of 10 dimes and 11 quarters is what Alexandra will have

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......is an example of
Stolb23 [73]

Answer:

The answer would be 'D'.

Step-by-step explanation:

An expression does NOT have an equal sign while a formula does. A variable is some letter symbol that you are solving for, but a constant would be a number such as 2 or 4 that could be added, multiplied, subtracted, or divided in an equation. 

I hope this helps!

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