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2 years ago

What is the Vertex and Y-intercept of f(x)=3x^2-6x+4? Please show your work.

Mathematics

1 answer:

xxMikexx [17]2 years ago

7 0

Answer:

(1;1) and (0;4)

Step-by-step explanation:

1) if given f(x)=3x²-6x+4 (where a=3; b=-6 and c=4), then

$x_0=\frac{-b}{2a}; \ = > \ x_0=1;$

$y_0=3*1-6*1+4=1;$

it means, the vertex has coordinates (1;1).

2) if according to the condition x=0, then

f(0)=0-0+4=4;

it means the Y-intercept is 4.

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An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a d

Anika [276]

Answers:

P(A) = 7/12

P(B) = 1/4

====================================================

Explanation:

Instead of having one die, let's say we have two dice. I'll make one red and the other blue.

I'll be using the dice chart shown below. The red and blue values add up to the black numbers inside the table. For instance, we have 1+1 = 2 in the upper left corner. There are 6*6 = 36 sums total.

Using that table, we can see the following:

There are 6 copies of "7"
There are 5 copies of "8"
There are 4 copies of "9"
There are 3 copies of "10"
There are 2 copies of "11"
There is 1 copy of "12"

In total, we have 6+5+4+3+2+1 = 21 instances where the two dice add to something larger than 6.

This is out of 36 ways to roll two dice.

Therefore P(A) = 21/36 = (3*7)/(3*12) = 7/12

-----------------------------------

If a number is divisible by 4, then it is a multiple of 4.

The multiples of 4 found in the table are: 4, 8, 12

We have

3 copies of "4"
5 copies of "8"
1 copy of "12"

This gives 1+5+3 = 9 values that are a multiple of 4

P(B) = 9/36 = (1*9)/(4*9) = 1/4

8 0

2 years ago

The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are

almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = the number that are not correctly calibrated.

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_3$

So, the required probability = $\frac{^{6}C_3}{^{8}C_3}$

= $\frac{20}{56}$ = 0.35

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_2$

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_1$

So, the required probability = $\frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}$

= $\frac{30}{56}$ = 0.54

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_1$

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_2$

So, the required probability = $\frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}$

= $\frac{6}{56}$ = 0.11

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0

3 years ago

Jesse bought 5.2 pounds of grapes for $7.75. Using the unit rate, how much would 3 pounds of grapes cost?

scZoUnD [109]

For 3 pounds it would be $4.47

3 0

3 years ago

You are road tripping down the California coast and you notice you need to fill up your gas tank. In CA, sales tax is 2.25%. You

amid [387]

Answer:

$1.26

Step-by-step explanation:

So you just have to find 2.25% of 56.

To find a certain percentage of something, you multiply it. Let's write out a sentence explaining what you need to do. You have to find:

2.25% of 56

Whenever you've got a sentence like this, all you've got to do is change the word "of" to a multiplication symbol. And now you've got an expression:

2.25% × 56

Let's convert the percentage to a decimal. To do this, you simply remove the percent symbol, then move the decimal point 2 places to the left.

2.25% = 0.0225

And now you have:

0.0225 × 56

Then you just do the math! I am assuming you already know how to do decimal multiplication so I'm not going to explain the process here.

But once you multiply 0.0225 × 56, you get an answer: 1.26

Hope this was helpful to you, and don't forget to choose the Brainliest answer!

7 0

3 years ago

Find x and Find y please

lbvjy [14]

Find x and y
X= 12
Y= 20

5 0

2 years ago

Read 2 more answers