Question

What is the Vertex and Y-intercept of f(x)=3x^2-6x+4? Please show your work.

Answer 1

Answer:

(1;1) and (0;4)

Step-by-step explanation:

1) if given f(x)=3x²-6x+4 (where a=3; b=-6 and c=4), then

$x_0=\frac{-b}{2a}; \ = > \ x_0=1;$

$y_0=3*1-6*1+4=1;$

it means, the vertex has coordinates (1;1).

2) if according to the condition x=0, then

f(0)=0-0+4=4;

it means the Y-intercept is 4.