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2 years ago

Answer asap!

Mathematics

2 answers:

Molodets [167]2 years ago

6 0

Answer:

4000 bags

Step-by-step explanation:

8 x 20 = 160 oz = 10 lb

2,000 lb = 1 ton

16 oz = 1b

2,000 x 16 = 32,000 oz = 1 ton

32,000/8 = 4,000 bags

matrenka [14]2 years ago

3 0

Answer:

160 ounces

Which is 10 pounds

And 4410 chip packets will equal about a ton

Step-by-step explanation:

because 20 x 8 =160

35274/8 = 4409.25

*note 35274 ounces is equal to a ton

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Diameter=14.6 round to nearest tenth

grandymaker [24]

The next greater tenth is 14.7
The next smaller tenth is 14.5

Neither of them is nearer to 14.6 than 14.6 already is.
So 14.6 is already the nearest tenth.

4 0

3 years ago

Read 2 more answers

Which expression is equal to 13 more than the quotient of n and 8

Juli2301 [7.4K]

Answer:

(n/8)+13

Step-by-step explanation:

6 0

3 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

What is the approximate value of x in the diagram below?

zavuch27 [327]

Answer:

Where is the diagram though..

Step-by-step explanation:

3 0

2 years ago

I need some help with this question

yarga [219]

Answer:

-7/15

Step-by-step explanation:

-4/5 translates to -12/15 and 1/3 translates to 5/15.

When you add -12/15+5/15 you get

-12+5/15 so you get -7/15

5 0

3 years ago