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hammer [34]
3 years ago
15

The theoretical probability of selecting a consonant at random from a list of letters in the alphabet is 21/26. Wayne opens a bo

ok, randomly selects a letter on the page and records the letter. He repeats the experiment 200 times. He finds p(consonant) = 60%. How does the theoretical probability differ from the experimental probability? What are some possible sources for this discrepancy. I will mark brainlest
Mathematics
2 answers:
zimovet [89]3 years ago
7 0

Answer:

Ask this question to high level boys or collage boys they will able to answer please mark me as the brainliest

Step-by-step explanation:

marysya [2.9K]3 years ago
6 0

Answer:

You need a corpus of text. It usually gathers text from passages, chapters, or sections of a book.

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Ryan had 40$ to buy an apple then on Tuesday he go 9$ how many dollars did he had in all
svlad2 [7]

Answer:

40 plus 9 is 49 simple math

Mark me as brainliest plz

5 0
3 years ago
Read 2 more answers
15x + 3 + 2x + 9r - (8 - r)
bezimeni [28]

Answer:

17x + 10r -5

Step-by-step explanation:

15x +3 + 2x + 9r- (8-r)

17x +3 +9r -8 +r

17x+ 10r+ -5

6 0
3 years ago
Can someone please help me with this???
Rom4ik [11]
The point would be (-5, 6). I hope I helped. 
3 0
3 years ago
3.) SOLVE FOR X.
gayaneshka [121]

The value of x in the secants intersection is 1 units

The value of NM in the tangent and secant intersection is 51 units

<h3>How to find length when secant and tangent intersect?</h3>

The first question, two secant intersect outside the circle.

Therefore,

(6x + 8x)8x = (9 + 7)7

14x(8x) = 16(7)

112x² = 112

x² = 112 / 112

x = √1

x = 1

The second question, tangent and secant intersect,

Therefore,

(x + 3)² = (x - 3)(16 + x - 3)

(x + 3)² = (x - 3)(x + 13)

(x + 3)(x + 3) = (x - 3)(x + 13)

x² + 3x + 3x + 9 = x² + 13x - 3x - 39

x² + 9x + 9 = x² + 10x - 39

x² - x² + 9x - 10x = -39 - 9

-x = - 48

x = 48

NM = 48 + 3 = 51 units

learn more on secant and tangent here: brainly.com/question/12477905

#SPJ1

6 0
1 year ago
The National Cancer Institute estimates that 3.65% of women in their 60s get breast cancer. A mammogram can typically identify c
masha68 [24]

Answer:

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Positive test.

Event B: Having breast cancer.

3.65% of women in their 60s get breast cancer

This means that P(B) = 0.0365

A mammogram can typically identify correctly 85% of cancer cases

This means that P(A|B) = 0.85

Probability of a positive test.

85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So

P(A) = 0.85*0.0365 + 0.05*0.9635 = 0.0792

What is the probability that a woman in her 60s who has a positive test actually has breast cancer?

P(B|A) = \frac{0.0365*0.85}{0.0792} = 0.3917

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

7 0
3 years ago
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