Out of 120 students in exam, 2/3 of them passed. How many students passed?
now,
no of students passed = 2/3×120
= 0.66×120
=80...
therefore <em>8</em><em>0</em><em> </em><em> </em><em>students</em><em> </em><em>were</em><em> </em><em>passed</em><em>.</em><em>.</em><em>.</em><em>.</em>
The answer is (-6, 5) for K.
In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Kx + Lx)/2 = Mx
(Kx + 8)/2 = 1
Kx + 8 = 2
Kx = -6
And now we do the same thing for y values
(Ky + Ly)/2 = My
(Ky + -7)/2 = -1
Ky + -7 = -2
Ky = 5
This gives us the final point of (-6, 5)
Answer:
it is 2766628276262626828373636737 points
Step-by-step explanation:
no explanation needed lol
The standard form of a line is in the form
A, B and C are integers, and A is positive. Let's start with multiplying the whole equation by 3 to get rid of denominators:
Subtract 3y from both sides:
Which of course is equivalent to
Which is the standard form, given the coefficients A=1, B=-3, C=6.
The greatest common factor of 135 225 and 270 is 135/225 = 3/5
hope you found this helpful ;)
