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Nataly_w [17]
2 years ago
8

Point (-4, -5) is located which quadrant?

Mathematics
1 answer:
jeka942 years ago
3 0

Answer:

D) Quadrant III

Step-by-step explanation:

The point (-4, -5) is located in the 3rd quadrant, in which both the x axis and the y axis are negative.

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Step-by-step explanation:

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inysia [295]
<h3>Answer:   14x - 8</h3>

=======================================================

Explanation:

I'll use the quadratic formula to find the roots or x intercepts. This slight detour allows us to factor without having to use guess-and-check methods.

The equation is of the form ax^2+bx+c = 0

  • a = 12
  • b = -11
  • c = -5

This leads to...

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-11)\pm\sqrt{(-11)^2-4(12)(-5)}}{2(12)}\\\\x = \frac{11\pm\sqrt{361}}{24}\\\\x = \frac{11\pm19}{24}\\\\x = \frac{11+19}{24} \ \text{ or } \ x = \frac{11-19}{24}\\\\x = \frac{30}{24} \ \text{ or } \ x = \frac{-8}{24}\\\\x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}

Now use those roots to form these steps

x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}\\\\4x = 5 \ \text{ or } \ 3x = -1\\\\4x - 5 =0 \ \text{ or } \ 3x+1 = 0\\\\(4x-5)(3x+1) = 0

Refer to the zero product property for more info.

Therefore, the original expression factors fully to (4x-5)(3x+1)

Use the FOIL rule to expand it out and you should get 12x^2-11x-5 again.

----------------------------------------------

We did that factoring so we could find the side lengths of the rectangle.

I'm using the fact that area = length*width

  • L = length = 4x-5
  • W = width = 3x+1

The order of length and width doesn't matter.

From here, we can then compute the perimeter of the rectangle

P = 2(L+W)

P = 2(4x-5+3x+1)

P = 2(7x-4)

P = 14x - 8

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F(x)=3x-3<br><br>g(x) 3x^3+5<br>Find F(-3) and g(-2)
astra-53 [7]

Answer:

f(-3) = -12

g(-2) = -19

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 3x - 3

g(x) = 3x³ + 5

f(-3) is <em>x</em> = -3 for function f(x)

g(-2) is <em>x</em> = -2 for function g(x)

<u>Step 2: Evaluate</u>

f(-3)

  1. Substitute in <em>x</em> [Function f(x)]:                                                                           f(-3) = 3(-3) - 3
  2. Multiply:                                                                                                             f(-3) = -9 - 3
  3. Subtract:                                                                                                            f(-3) = -12

g(-2)

  1. Substitute in <em>x</em> [Function g(x)]:                                                                         g(-2) = 3(-2)³ + 5
  2. Exponents:                                                                                                        g(-2) = 3(-8) + 5
  3. Multiply:                                                                                                            g(-2) = -24 + 5
  4. Add:                                                                                                                   g(-2) = -19
4 0
3 years ago
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