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2 years ago

Point (-4, -5) is located which quadrant?

Mathematics

1 answer:

jeka942 years ago

3 0

Answer:

D) Quadrant III

Step-by-step explanation:

The point (-4, -5) is located in the 3rd quadrant, in which both the x axis and the y axis are negative.

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What is 5(n-1)=2(n-4)-6

Shalnov [3]

Answer:

Step-by-step explanation

6n - 6 = 2 (n+1)

Simplify 2 (n+1)

6n - 6= 2n +2

Move all terms related to n to the left side of the equation

4n -6 =2

Move all terms not related to n to the right side of the equation

4n =8

Divide each term by 4 then simplify

n=2

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2 years ago

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2 years ago

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Jason complete 5/8 of his test and 10/25 of his homework. What fraction of his homework does he still need to complete?

sineoko [7]

Answer:

3/4

Step-by-step explanation:

Because the total homework would be 25/25

$\frac{25}{25}-\frac{10}{25} =\frac{15}{25}$

15/20 can be reduced to 3/4

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3 years ago

What is a good strategy for finding the distance between two numbers on a number line?

Gnom [1K]

The strategy is following
Smaller number subtract from the greater. Result is distance between two numbers

For example you have 3 and 8
8-3-5
5 is the distance between 3 and 8
It also works with the negative numbers, for example 3 and -5
3-(-5)=8

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3 years ago

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time ca

aleksandr82 [10.1K]

Answer:

(a)8.0mg

(b)36.87 hours

(c)-0.168

Step-by-step explanation:

The amount of Valium in that person's bloodstream at any time can be modeled with the exponential decay function $A ( t ) = 10 e^{ -0.0188 t$ (t in hours)

(a)After 12 Hours

$A ( 12) = 10 e^{ -0.0188*12}\\=7.98\\\approx 8.0 mg $(to the nearest tenth of a milligram)$

(b)If A(t)=5mg

Then:

$5= 10 e^{ -0.0188 t}\\$Divide both sides by 10\\0.5=e^{ -0.0188 t}\\$Take the natural logarithm of both sides\\ln (0.5)=-0.0188 t\\t=ln (0.5) \div (-0.0188)\\$t=36.87 hours (to two decimal places.)$

(c)

$A ( t ) = 10 e^{ -0.0188 t}\\A'(t)=10(-0.0188)e^{ -0.0188 t}\\A'(t)=-0.188e^{ -0.0188 t}\\$At 6 hours, the rate at which the amount of Valium is decaying therefore is:\\A'(6)=-0.188e^{ -0.0188*6}\\$=-0.168 ( to three decimal places)$

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2 years ago