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laila [671]
2 years ago
6

You must select a team from a group of 6 boys and 10 girls. How many ways can you select 2 boys and 5 girls?

Mathematics
1 answer:
Keith_Richards [23]2 years ago
6 0

Using the combination formula, it is found that you can select 2 boys and 5 girls in 2,520 ways.

In this problem, Joao and Elisa would be the same team as Elisa and Joao, hence the order is not important and the <em>combination formula</em> is used to solve this question.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem:

  • 2 boys are selected from a set of 6.
  • 5 girls are selected from a set of 10.

Hence:

T = C_{5,2}C_{10,5} = \frac{5!}{3!2!} \times \frac{10!}{5!5!} = 2520

You can select 2 boys and 5 girls in 2,520 ways.

More can be learned about the combination formula at brainly.com/question/25821700

#SPJ1

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option C is correct i.e., ∠E ≅∠H.

explanation:

it is given that ratio of corresponding sides of ΔFGE and ΔIJH are equal

i.e.,  

\frac{GE}{JH}=\frac{EF}{HI}

and if ∠E ≅ ∠H

Then ΔFGE and ΔIJH are similar by SAS (side angle side) similarity theorem.  

so option C is correct i.e.,  ∠E ≅ ∠H.

and option B is also correct

explanation:

since it is given that

\frac{FG}{IJ}=\frac{EF}{HI}

And if ∠I ≅ ∠F

then  ΔFGE and ΔIJH are similar by SAS (side angle side) similarity theorem.  

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here's the solution,

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Step 2: Subtract 2 from both sides.

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Step 3: Divide both sides by -8.

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Answer:

x=−1

☆ Hopefully this helps. :)

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