Answer:
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
Step-by-step explanation:
Given:
Length of drive way at garage door = 12 feet
Length of drive way at street = 20 feet
Length of total driveway = 18 feet
Find:
Amount of Winter sealer for 2 coats[in square feet]
Computation:
Amount of Winter sealer for 2 coats[in square feet] = 2[Area of trapezoid]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(Sum of parallel side)(Height)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(12 + 20)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(32)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 32 x 18
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
Answer:
There is not enough evidence to reject the null hypothesis.
Their sum is greater than the probability value , the data does not fit the experiment and the null is accepted.
Step-by-step explanation:
There are 3 colors so degrees of freedom = 3-1 = 2
The chi square value = 0.85
The p value for chi square =0.85 for 2 degrees of freedom for the left tailed test to be 0.34623 for 0.1,0.05 and 0.01 significance level.
There is not enough evidence to reject the null hypothesis.
The p value for chi square =0.85 for 2 degrees of freedom for the right tailed test to be 0.65377 for 0.1,0.05 and 0.01 significance level.
There is not enough evidence to reject the null hypothesis.
Their sum is greater than the probability value , the data does not fit the experiment and the null is accepted.
Factor out 12x^3y^2
12x^3y^2(3y^2+5x^ 2 y z^2 -1)
(48a^3 + 32a^2 + 16a) / 4a = ?
48a^3 / 4a = 12a^2
32a^2 / 4a = 8a
16a / 4a = 4
so
(48a^3 + 32a^2 + 16a) / 4a = 12a^2 + 8a + 4
Answer is D. 12a^2 + 8a + 4
If im understanding this correctly, to find the value of the car after x amount of years, the answer would be 17,500 - 750(x)
