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klemol [59]
3 years ago
12

Rewrite sin^4xtan^2x in terms of the first power of the cosine

Mathematics
1 answer:
Vikki [24]3 years ago
7 0
\sin ^4 x \tan ^2 x = \dfrac{\sin ^4 x\ \sin ^2 x }{\cos ^2 x} = \dfrac{\sin^6 x}{\cos ^2 x} = \dfrac{(\sin ^2 x)^3}{\cos^2 x}=\dfrac{(1-\cos^2 x)^3}{\cos^2 x}
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