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Ganezh [65]
3 years ago
10

If Jk _| lm which statement is true?

Mathematics
2 answers:
Nutka1998 [239]3 years ago
7 0
It’s the first option, hope this helps
nikdorinn [45]3 years ago
4 0
It is the first option i think
You might be interested in
i am 7 digit number my digit are fromed as the skip count of 3 by 4 times find the place value of my middle digit
yaroslaw [1]

Answer:

7 is in thousands place and its place value is 7000, 2 is in hundreds place and its place value is 200, 6 is in ten place and its place value is 60, 3 is in ones place and its place value is 3.

0, 1, 2, 3, 4, 5, 6, 7, 8, 9. The place value of a 3-digit number helps in understanding the value of each of the digits. The smallest of 3-digit numbers is 100 and the largest number is 999.

Step-by-step explanation:

3 0
3 years ago
Please someone actually help with this I don't understand how.​
tigry1 [53]

Answer:

Scatter plot

Step-by-step explanation:

Answer is 5

8 0
3 years ago
Subtract using the number line -3/5 - (-2/5) (picture provided)
lara31 [8.8K]

Answer:

<h2>-1/5</h2>

Step-by-step explanation:

Starting at -3/5 you need to subtract -2/5.

When you subtract a negative number, the sign flips and you add instead. Often, you are taught that two similar signs means add and two opposite signs mean minus.

<em>+ + = +</em>

<em>- - = -</em>

<em>+ - = -</em>

<em>- + = -</em>

<em />

This means -3/5 - -2/5 becomes -3/5 + 2/5.

Because you are adding, you move two lines to the right on the number line.

You end at -1/5.

5 0
3 years ago
Read 2 more answers
A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

5\cdot 36^5

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8

ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8

oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

7 0
3 years ago
In the diagram, line a is the perpendicular bisector of km. what is the length of km?
sleet_krkn [62]

Answer:

80

Step-by-step explanation:

From the given diagram;

KN = NM

9x - 5 = 7x + 7

9x - 7x = 7 + 5

2x = 12

x = 12/2

x = 6

Since KM= 2KL

KM = 2(6x+4)

KM = 12x + 8

KM = 12(6)+8

KM = 72+8

KM = 80

Hence the length of KM is 80

6 0
3 years ago
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