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Soloha48 [4]
3 years ago
6

Help me find the measure of angle W please its trigonometry

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
8 0
71° + 90° + w = 180°
w = 19°
hope it helps☺
kap26 [50]3 years ago
7 0
The sum of angles in a triangle is 180 drgrees.
From the picture I see that in the triangle UVW has angle U =90 degees, angle V=71 degrees so
W= 180-90-71= 19 drgrees

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What is the value of 2 ^ 3
Setler79 [48]

Answer:

8

Step-by-step explanation:

2^3 is the same as 2 x 2 x 2

2 x 2 is 4 and 4 x 2 is 8

so 2^3 is 8

3 0
3 years ago
Read 2 more answers
Please help ASAP!!!
PolarNik [594]
Use the formula 42600 ÷ (6.9 ÷<span> 100) to calculate this !

</span>42,600 ÷ (6.9 ÷ 100) = <span>617391.304348. Round this to 617391 since you can't sell a percentage of a book.
</span>
To check this, calculate 6.9 percent of 617391.304348. 0.069 · 617391.304348 = 42,600.
6 0
3 years ago
67+65+ what gives me 180
Serga [27]

Answer:

48.

Step-by-step explanation:

To find the missing number write out the equation :

67 + 65 + ? = 180.

67 + 65 = 132

To find out how much more we need you can minus 132 from 180.

180 - 132 = 48.

Plug it in to see if it works.

67 + 65 + 48 does equal 180.

Hope this helps,

Davinia.

4 0
3 years ago
What is the opposite of the number 657,987?
evablogger [386]

Answer: -657,987

Step-by-step explanation:

8 0
3 years ago
The altitude of a triangle is increasing at a rate of 1.5 1.5 centimeters/minute while the area of the triangle is increasing at
seraphim [82]

Answer:

The base reduces at 3.75cm/min

Step-by-step explanation:

Given

Let

h \to altitude

b \to base

A \to Area

So:

\frac{dh}{dt} = 1.5cm/min

\frac{dA}{dt} = 1.5^2cm/min

The area of a triangle is:

A = \frac{1}{2}bh

Calculate b when A =88cm^2; h =8cm

A = \frac{1}{2}bh

88=\frac{1}{2} * b * 8

88 =b * 4

Solve for b

b = 88/4

b = 22

We have:

A = \frac{1}{2}bh

Differentiate with respect to time

\frac{dA}{dt} =\frac{1}{2}(h\frac{db}{dt} + b\frac{dh}{dt})

Substitute the following values in the above equation

\frac{dh}{dt} = 1.5cm/min        \frac{dA}{dt} = 1.5^2cm/min      b = 22     h = 8

1.5 = \frac{1}{2}(8 * \frac{db}{dt} + 22 * 1.5)

Multiply both sides by 2

3 = 8 * \frac{db}{dt} + 22 * 1.5

3 = 8 * \frac{db}{dt} + 33

Collect like terms

8 * \frac{db}{dt} = 3 -33

8 * \frac{db}{dt} = -30

Divide both sides by 8

\frac{db}{dt} = -\frac{30}{8}

\frac{db}{dt} = -3.75

4 0
3 years ago
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