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s344n2d4d5 [400]
2 years ago
6

The average attendance at school for 5 days was 264. If the attendance on the 5th day was 256, calculate the average attendance

for the first 4 day’s
Mathematics
1 answer:
Tema [17]2 years ago
5 0

Answer:

266

Step-by-step explanation:

Let the attendence of 5days be a,b,c,d,e

given,

(a+b+c+d+e)/5=264

a+b+c+d+256=264*5 [since 5th day=256]

(a+b+c+d+)/4=1(320-256)/4 [dividing both side by 4]

average attendence of 4 days =266

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A bride and groom both invited guests to their wedding. The bride invited twice as many women as the groom did, and the groom in
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Answer:

option 1) 50

Step-by-step explanation:

Let m and w denote the men and women respectively.

From the question, if the groom invited w number of women, then bride invited 2w number of women.

Also, if the bride invited m number of men,then the groom invited 2m.

Hence we can write the following maths equation:

w+2m=105.........1

2w+m=135.........2

We multiply eqn(1) by 2 to get eqn(3)

This implies that,

2w+4m=210.......3

We then subtract eqn (2) from eqn(3) to obtain;

3m=75

we divide through by 3

\implies \frac{3m}{3} = 75

\implies m= 25

Substituting the value of m into eqn (1)

to find the value for w

\implies w + 50 = 105

subtracting 50 from both sides.

\implies w + 50  - 50= 105 - 50

\implies w+2(25)=105

\implies w= 55

So we can say the :

bride invited 25 men and 110 women,

groom invited 50 men and 55 women.

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