1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Slav-nsk [51]
3 years ago
11

Can you substarct in any order?

Mathematics
2 answers:
fiasKO [112]3 years ago
7 0

Answer:

No

Step-by-step explanation:

In subtracting, you must start with the larger number

Sauron [17]3 years ago
4 0
Yes but you will end up with a negative number
You might be interested in
n automatic machine in a manufacturing process is operating properly if the lengths of an important subcomponent are normally di
Paraphin [41]

Answer:

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.

This means that \mu = 116, \sigma = 5.4

Find the probability that one selected subcomponent is longer than 118 cm.

This is 1 subtracted by the pvalue of Z when X = 118. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{118 - 116}{5.4}

Z = 0.37

Z = 0.37 has a pvalue of 0.6443

1 - 0.6443 = 0.3557

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

8 0
3 years ago
FIND THE NEXT NUMBER IN THE SEQUENCE.<br><br> 4, 9, 16, 25,
Norma-Jean [14]

Answer:

The next number in the sequence is 36.

Step-by-step explanation:

Consider the provided sequence.

4, 9, 16, 25

The number 4 can be written as 2².

The number 9 can be written as 3².

The number 16 can be written as 4².

The number 25 can be written as 5².

The general term of the sequence is: a_n=(n+1)^2

Thus, the next term will be:

a_5=(5+1)^2

a_5=(6)^2

a_5=36

Therefore, the next number in the sequence is 36.

6 0
3 years ago
Determine algebraically whether f(x) = 3 is even or odd.
Artist 52 [7]

Answer:

f(x) is even

Step-by-step explanation:

f(x) = 3

f(-x) = 3

f(x) = f(-x)

3 0
3 years ago
A ship sails 250km due North qnd then 150km on a bearing of 075°.1)How far North is the ship now? 2)How far East is the ship now
olga_2 [115]

Answer:

1)  288.8 km due North

2)  144.9 km due East

3)  323.1 km

4)  207°

Step-by-step explanation:

<u>Bearing</u>: The angle (in degrees) measured clockwise from north.

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

<u>Cosine rule</u>

c^2=a^2+b^2-2ab \cos C

where a, b and c are the sides and C is the angle opposite side c

-----------------------------------------------------------------------------------------------

Draw a diagram using the given information (see attached).

Create a right triangle (blue on attached diagram).

This right triangle can be used to calculate the additional vertical and horizontal distance the ship sailed after sailing north for 250 km.

<u>Question 1</u>

To find how far North the ship is now, find the measure of the short leg of the right triangle (labelled y on the attached diagram):

\implies \sf \cos(75^{\circ})=\dfrac{y}{150}

\implies \sf y=150\cos(75^{\circ})

\implies \sf y=38.92285677

Then add it to the first portion of the journey:

⇒ 250 + 38.92285677... = 288.8 km

Therefore, the ship is now 288.8 km due North.

<u>Question 2</u>

To find how far East the ship is now, find the measure of the long leg of the right triangle (labelled x on the attached diagram):

\implies \sf \sin(75^{\circ})=\dfrac{x}{150}

\implies \sf x=150\sin(75^{\circ})

\implies \sf x=144.8888739

Therefore, the ship is now 144.9 km due East.

<u>Question 3</u>

To find how far the ship is from its starting point (labelled in red as d on the attached diagram), use the cosine rule:

\sf \implies d^2=250^2+150^2-2(250)(150) \cos (180-75)

\implies \sf d=\sqrt{250^2+150^2-2(250)(150) \cos (180-75)}

\implies \sf d=323.1275729

Therefore, the ship is 323.1 km from its starting point.

<u>Question 4</u>

To find the bearing that the ship is now from its original position, find the angle labelled green on the attached diagram.

Use the answers from part 1 and 2 to find the angle that needs to be added to 180°:

\implies \sf Bearing=180^{\circ}+\tan^{-1}\left(\dfrac{Total\:Eastern\:distance}{Total\:Northern\:distance}\right)

\implies \sf Bearing=180^{\circ}+\tan^{-1}\left(\dfrac{150\sin(75^{\circ})}{250+150\cos(75^{\circ})}\right)

\implies \sf Bearing=180^{\circ}+26.64077...^{\circ}

\implies \sf Bearing=207^{\circ}

Therefore, as bearings are usually given as a three-figure bearings, the bearing of the ship from its original position is 207°

8 0
2 years ago
Read 2 more answers
The system of equations below has no solution.
mixer [17]

Answer:

  • Second option: 0 = 26

Explanation:

This is the given system of equations:

\frac{2}{3} x+\frac{5}{2} y=15\\ \\ 4x+15y=12

A linear combination of the system is any equation formed by the algebraic addition of both equations, one or both multiplied by an arbitrary constant.

To prove that the given system has no solution you could multiply the first equation times 6 (to get rid of the fractions), multiply the second equation times - 1, and add the two results:

<u>1. First equation times 6:</u>

6\times\frac{2}{3} x+6\times\frac{5}{2}y=6\times 15\\ \\ 4x+15y=90

<u />

<u>2. Second equation times - 1:</u>

-4x-15y=-12

<u />

<u>3. Add the two new equations:</u>

0=78

<u />

<u>4. Conclusion:</u>

Since 0 = 78 is false, no matter what the value of x and y are, the conclusion is that the system of equations has not solution.

The only choice that represents that same situation is the second one, 0 = 26. That is a possible linear combination that represents that the system of equations has no solutions.

In fact, you might calculate the exact factors by which you had to multiply each one of the original equations to get 0 = 26, but it is not necessary to tell that that option represents a possible linear combination for the given system of equations.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Write an example of the distributive property.
    12·2 answers
  • Joe is preparing 18 hot dogs for his party. However, Joe only has 12 hot dog buns. How many more hot dog buns does Joe need
    9·1 answer
  • Covert 3.92 into a mixed number in simplest from
    5·2 answers
  • The sum of two numbers is 28 . The first number, x, is three times the second number,y. Which system of equations can be used to
    7·2 answers
  • Hhhhhhh i need helpp
    14·1 answer
  • Can someone please help me with this?
    14·1 answer
  • Mr. Martinez has 3 ice chests. He is placing 14 lunches in each ice chest. Each lunch contains a sandwich, a bag of chips, and a
    9·2 answers
  • What’s the slope and y intercept of all of them
    8·1 answer
  • Arrange the numbers 3.011, 3.11 and 3.1 in descending order.
    11·1 answer
  • What other circle theorems can cyclic quadrilaterals can be related to? Explain how.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!