Question

The height of an object after it is released can be modeled by the function f (x) = negative 16 t squared v t s, where t is the number of seconds after the object is released, v is the upward speed in feet per second at release, and s is the starting height in feet. if a quarterback throws a ball from his hand 6 feet in the air at an upward speed of 25 feet per second, how much time does his teammate have to catch the ball?

Answer 1

The amount of time his teammate have to catch the ball is equal to 1.774 seconds.

Given the following function:

• f(x) = -16t² + vt + s.

• Displacement, s = 6ft.

• Velocity, v = 25 ft/s.

How to calculate the amount of time?

In order to determine the amount of time his teammate have to catch the ball, we would evaluate the given position-time function as follows:

f(t) = -16t² + 25t + 6.

In Mathematics, the standard form of a quadratic equation is given by;

ax² + bx + c =0

Where:

a = -16.

b = 25.

c = 6.

Solving the function by using the quadratic formula, we have:

t = [-b ± √(b² - 4ac)]/2a

t = [-25 ± √[(25² - 4(-16)(6))]/2(-16)

t = [25/32 ± (-1/32)√1009]

t = 25/32 ± (-0.993)

t = 0.781 ± 0.993

t = 0.781 + 0.993

Time, t = 1.774 seconds.

Note: We ignored the negative value because time cannot be negative.

Read more on quadratic equation here: brainly.com/question/1214333