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3 years ago

Two teammates were comparing data from five basketball games.

Mathematics

1 answer:

sdas [7]3 years ago

6 0

Answer:

The answer is andrew!

Step-by-step explanation:

andrew 10 + 14 + 8 + 12 + 11/ 5 = 11

leroy 2 + 12 + 9 + 11 + 16/5 = 10

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How is a marketing -oriented firm different from a production-oriented firm or a sales-oriented firm?

dedylja [7]

Marketing-oriented firms focus more on what the market needs above every other aspects.

<h3>What is a Marketing-oriented Firm?</h3>

Marketing-oriented firms can be described as firms that major in identifying the needs and wants of customers and then creating specific products that are designed to meet the wants of such customers. One of the important elements of marketing-oriented firms is to ensure there is a demand for whatever products or services they offer.

Some examples of marketing-oriented firms are:

Apple
Coca-Cola
Amazon

<h3>What is a Product-oriented Firm or a Sales-oriented Firm?</h3>

A product-oriented firm focus more resources on and focus on researching and developing quality products rather than focusing more on the market to discover the wants of customers.

Sales-oriented firm tend to focus more on developing its sales force that will promote their products and services.

<h3>How Marketing-Oriented Firms are Different from the Product-oriented or Sales-oriented Firms?</h3>

Marketing-oriented firms stand out and are different from the other two types of firms because they focus more on what the market needs above every other aspects.

Learn more about Marketing-oriented firms on:

brainly.com/question/13288643

#SPJ1

4 0

2 years ago

(a)5%)Let fx, y) = x^4 + y^4 - 4xy + 1. and classify each critical point Find all critical points of fx,y) as a local minimum, l

lara31 [8.8K]

$f(x,y)=x^4+y^4-4xy+1$

has critical points wherever the partial derivatives vanish:

$f_x=4x^3-4y=0\implies x^3=y$

$f_y=4y^3-4x=0\implies y^3=x$

Then

$x^3=y\implies x^9=x\implies x(x^8-1)=0\implies x=0\text{ or }x=\pm1$

If $x=0$ , then $y=0$ ; critical point at (0, 0)
If $x=1$ , then $y=1$ ; critical point at (1, 1)
If $x=-1$ , then $y=-1$ ; critical point at (-1, -1)

$f(x,y)$ has Hessian matrix

$H(x,y)=\begin{bmatrix}12x^2&-4\\-4&12y^2\end{bmatrix}$

with determinant

$\det H(x,y)=144x^2y^2-16$

At (0, 0), the Hessian determinant is -16, which indicates a saddle point.
At (1, 1), the determinant is 128, and $f_{xx}(1,1)=12$ , which indicates a local minimum.
At (-1, -1), the determinant is again 128, and $f_{xx}(-1,-1)=12$ , which indicates another local minimum.