Answer:
<h3>y - 3 = 2(x+1)</h3>
Step-by-step explanation:
The equation of the line in point slope form is expressed as;
y - y0 = m(x-x0)
m is the slope
(x0, y0) is a point on the line
Get the slope;
Given the points (-1,3) and (1, 7)
m = y2-y1/x2-x1
m = 7-3/1+1
m = 4/2
m = 2
Substitute the point m = 2 and the point (-1, 3) into the formula above as shown;
y - y0 = m(x-x0)
y - 3 = 2(x-(-1))
y - 3 = 2(x+1)
Hence the required equation is y - 3 = 2(x+1)
Answer:
<h2>x = - 1.14 or x = 2.64</h2>
Step-by-step explanation:
2x² - 3x - 6 = 0
Using the quadratic formula
a = 2 , b = - 3 , c = 6
Substituting the values into the above formula
We have
We have the final answer as
<h3>x = - 1.14 or x = 2.64</h3>
Hope this helps you
Answer:
m<B = 60°
m<C = 60°
m<F = 80°
m<G = 80°
Step-by-step explanation:
m<B = 180° - 120° = 60°
m<C = m<B = 60° (Vertically opposite angles are equal)
m<F = 180° - (40° + m<C(60°)) = 80°
m<G = 180° - (m<H + m<B) = 180° - (40° + 60°) = 80°
Answer:
I dont know what you mean wdym...
Step-by-step explanation:
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
