Answer:
Adult ticket: $7
Child ticket: $2
Step-by-step explanation:
Set up a system of equations where a represents the cost of one adult ticket and c is the cost of one child ticket:
2a + 3c = 20
a + 4c = 15
Solve by elimination by multiplying the bottom equation by -2:
2a + 3c = 20
-2a -8c = -30
Add them together:
-5c = -10
c = 2
Now, we can plug in 2 as c to find the value of a:
2a + 3c = 20
2a + 3(2) = 20
2a + 6 = 20
2a = 14
a = 7
Answer:
44.1 x 10^-2
Step-by-step explanation:
Since one grain
= 7 x 10^-5
6300kg = 7 x 10^-5 x 6300
Put 6300 in standard form
7 x 10^-5 x 6.3 x 10^3
Multiply the whole numbers and add the exponents
7 x 6.3 x 10^-5 + 3
44.1 x 10^-2
There are 44.1 x 10^-2 grains of sand in 6300kg
Answer:
The margin of error (E) 
Step-by-step explanation:
Given,
mean 
standard deviation 
sample size 

Critical value


Critical value 


The margin of error (E) 


Hence, The margin of error (E) 
Complete question is attached in below.
Answer:
It's Same perimeter only
Step-by-step explanation:
It can't be the other two because they don't share the same area