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3 years ago

jenna has 4 double fudge brownies to share with 5 people including yourself how can jenna share the brownies equally.

Mathematics

2 answers:

Oliga [24]3 years ago

6 0

Answer:

4÷5=0.8 or 4/5

Step-by-step explanation:

Sidana [21]3 years ago

4 0

Answer: 4/5 or 0.8

Step-by-step explanation: So if Jenna has four and she wants to split it up into 5 equal parts. She'd have to split it into 5 pieces of 4/5. to figure this out, all you have to do is divide 4 by 5. My teachers would tell me that all fractions are also a division problem as in if we take the first number we're dividing by and make it the numerator, and then make the second one the denominator then we can find out the answer.

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The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth

Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = $P(Laptop) = p_{X} = \frac{4}{9}$

The probability of selecting a desktop is = $P(Desktop) = p_{Y} = \frac{5}{9}$

Then both X and Y follows Binomial distribution.

$X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})$

The probability function of a binomial distribution is:

$P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}$

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: ${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

${8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70$

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

$P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\ =0.304832\\\approx0.305$

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

$P(Y\geq 3)=1-P(Y$

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0

3 years ago

Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra $28,000 over the next 6 year

Anna35 [415]

Given:

• Amount to save, A = $28,000

• Time, t = 6 years

• Interest rate, r = 5.3% ==> 0.053

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

$FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})$

Where:

FV is the future value = $28,000

r = 0.053

n = 4

t = 6 years

Thus, we have:

$28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}$

Let's solve for P.

We have:

$\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\ \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\ \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\ \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}$

Solving further:

$28000=P(28.0384237)$

Divide both sides by 28.0384237:

$\begin{gathered} \frac{28000}{28.0384237}=\frac{P(28.0384237)}{28.0384237} \\ \\ 998.6=P \\ \\ P=998.6 \end{gathered}$

Therefore, the amount that must be deposited quarterly into the account is $998.60

ANSWER:

$998.60

8 0

1 year ago

Raven makes lanyards to sell at the craft fair. Each lanyard requires 1.5 feet of. At the fabric store, fabric is sold by foot.

hoa [83]

That was said oddly. From what I understand, she would need to buy 64 feet of fabric.

4 0

3 years ago

Read 2 more answers

Giving a test to a group of students, the grades and gender are summarized below

GenaCL600 [577]

Answer:

59 / 71

Step-by-step explanation:

Given the data :

A B C Total

Male 20 10 13 43

Female 15 2 11 28

Total 35 12 24 71

The probability of randomly selecting a Student that got B ;

Probability = required outcome / Total possible outcomes

P(getting B) = number of students who got B / total number of students

P(getting B) = 12 / 71

Probability of getting B = 12 /71

Probability of not getting B = P(getting B)' = 1 - P(getting B)

Probability that student did not get "B" = 1 - 12/71 = 59 / 71

7 0

3 years ago

Write a quadratic equation in factored form to model the given problem. Be sure to write the entire equation.

MAXImum [283]

Base= x
Height= 4+x

Area = (1/2)(x)(4+x) = 6

Hence, quadratic equation is,

(x)(8+2x) = 12

5 0

3 years ago