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Pavlova-9 [17]
2 years ago
5

can somebody please help me with this I have school in 4 minutes and I need to get this done but I don't understand it at all an

d my teachers gonna tell at me if I don't get it and I'm really embarrassed​

Mathematics
1 answer:
GuDViN [60]2 years ago
3 0
Yes I think I’m gonna go go to go home with homework homework done today I will be there in green bath
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Johan always wears a shirt, pants, socks, and shoes. He owns 20 pairs of socks, 5 pairs of shoes, 10 pairs of pants, and 8 shirt
DerKrebs [107]

Answer:

Johan can make 8000 different outfits.

Step-by-step explanation:

Johan needs to pick one of each (shirt, pants, socks and shoes) to make a outfit. The number of socks he has is 20 pairs, so he has 20 possibilities for socks. In the same way, the number of possibilities for shoes is 5, for pants is 10 and for shirts is 8.

So, to find the number of outfits he can make, we need to multiply all the possibilities for each case, so:

Number of different outfits = 20 * 5 * 10 * 8 = 8000.

6 0
3 years ago
Read 2 more answers
Find the sum of the following ap .1) 1/15, 1/12, 1/10,....,to 11 terms​
sertanlavr [38]

Answer:

33/20

Step-by-step explanation:

1/12 - 1/15 = 5/60 - 4/60 = 1/60

d = 1/60

a_n = a_1 + d(n - 1)

a_11 = 1/15 + (1/60)(11 - 1)

a_11 = 1/15 + 1/6

a_11 = 4/60 + 10/60

a_11 = 14/60

a_11 = 7/30

a_12 = 14/60 + 1/60

a_12 = 15/60

a_12 = 1/4

s_n = n(a_1 + a_n)/2

s_11 = 11(1/15 + 7/30)/2

s_11 = 11(2/30 + 7/30)/2

s_11 = 11(9/30)/2

s_11 = 99/60

s_11 = 33/20

8 0
3 years ago
Complete the scale by labeling the remaining tick marks​
scoundrel [369]

Answer:

Can you provide a picture?

I cannot help you if you don't.

5 0
2 years ago
A student worked out at a gym continuously for 50 minutes. The graph shows the remaining percentage of the workout as a linear f
Monica [59]

Small problem....

There is no graph!

ill be happy to solve this if i saw a graph

5 0
2 years ago
Let ŷ represent the profit (in thousands of dollars) for a certain company x years after 1970. A statistician calculates a linea
Anika [276]

Answer:

$17,280

Step-by-step explanation:

The model for profit (y), in thousands of dollars, as a function of time (x), in years after 1970 is:

y=0.66x +12

The corresponding value of x in 1978 is:

x= 1978-1970\\x=8

Estimating the profit (in thousands of dollars) in 1978:

y(8)=0.66*8 +12\\y(8) = 17.28

Converting it to dollars:

P = \$1,000*y(8)= \$1,000*17.28\\P= \$17,280

The estimated profit in 1978 is $17,280.

5 0
3 years ago
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