Answer:
1.1 × 10⁻⁶ M
Explanation:
Step 1: Given and required data
- Concentration of Ca²⁺ ([Ca²⁺]): 2.5 mM = 2.5 × 10⁻³ M
- Calcium oxalate solubility product constant (Ksp): 2.7 × 10⁻⁹
Step 2: Write the balanced equation for the solution reaction of calcium oxalate
CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)
Step 3: Calculate the concentration of the oxalate ion to begin the precipitation of calcium oxalate
We will use the Ksp of calcium oxalate.
Ksp = 2.7 × 10⁻⁹ = [Ca²⁺].[C₂O₄²⁻]
[C₂O₄²⁻] = Ksp / [Ca²⁺]
[C₂O₄²⁻] = 2.7 × 10⁻⁹ / 2.5 × 10⁻³
[C₂O₄²⁻] = 1.1 × 10⁻⁶ M
Answer:
Match the words to the definitions.
Explanation:
1. F
2. A
3. C
4. E
5. B
6. D
7. B
8. F
9. A
10. E
11. D
12. C
13. B
<span> A compound <span>lens microscope. </span></span>
solution:
1000 = m*2400*(78-22) + m*8.79*10^5
1000= 134400m + 879000m
1000= 1030200m
m = 1000/1013400
m= 1013.4 grams
the final answer is 0.9706 grams
