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Strike441 [17]
3 years ago
6

Which condition increases the number of collisions between reactant molecules in a given volume?

Chemistry
2 answers:
Nezavi [6.7K]3 years ago
4 0

Answer:

Increasing Surface Area

Explanation:

A greater surface area (meaning more, smaller particles) allows for more opportunity for particles to collide.  On the other hand, decreasing temperature and removing a catalyst would only decrease the number of collisions, and the clumping option doesn't make much sense.  Hope this helps!

Nata [24]3 years ago
3 0

Answer:

Increasing Surface Area

Explanation:

Chemical reactions occur at the atomic level where the atoms of each reacting elements interact with one another to form products. However, one way this interaction occurs is via COLLISION OF ATOMIC PARTICLES. In accordance with the collision theory, a collision must occur between reactant atomic particles in order for a reaction to take place.

However, certain factors affect the rate at which this collision occurs. One of them is the SURFACE AREA OF THE REACTANTS. Increasing the surface area of reactants simultaneously increases the frequency at which particles collide. Hence, INCREASING SURFACE AREA increases the number of collisions between reactant molecules in a given volume.

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What the correct answer ​
stellarik [79]

Answer:

Alkali metals are elements found in group 1 of the Periodic Table. Alkali metals are soft, malleable, ductile, and are good conductors of heat and electricity. They have low melting and boiling points compared to most other metals.

7 0
3 years ago
Could a mixture be made up of only one element and no compounds​
Firdavs [7]

Yes. A mixture can be made up of just elements without the use of a compound, you can also just use compounds in a mixture without any elements

5 0
3 years ago
Molarity of 2%W/V of NaOH is
TiliK225 [7]
Assume it is 1 litre and weighs 1kg.
2 percent of 1 kg is 20g.
20g divided by molar mass of NaOH.
20g divide by 40 = 0.5 mole
0.5 mole in a litre would be 0.5M
That is the answer: 0.5M
6 0
3 years ago
Determine the amount in grams of kcl that exists in 20.3 g of a solution that contains 1.14 % KCI by mass.
artcher [175]

Answer:

0.23 g

Explanation:

From the question given above, the following data were obtained:

Mass of solution = 20.3 g

Percentage by mass of KCl = 1.14%

Mass of KCl =?

The mass of KCl in the solution can be obtained as follow:

Percentage by mass = mass of solute / mass of solution × 100

1.14% = mass of KCl / 20.3

Cross multiply

Mass of KCl = 1.14% × 20.3

Mass of KCl = 1.14/100 × 20.3

Mass of KCl = 0.0114 × 20.3

Mass of KCl = 0.23 g

Therefore, the mass of KCl in the solution is 0.23 g

6 0
3 years ago
When calcium metal (Ca) reacts with oxygen gas (O2), it produces the ionic compound calcium oxide (CaO). Write the balanced equa
jonny [76]

Oxidation-Reduction Reactions Suggested Reading Thus the oxidation number for oxygen in calcium oxide is -2. ... In effect, each calcium atom loses two electrons to form Ca2+ ions, and each O atom in O2 gains two electrons to form O2- ions. The net result is a transfer of electrons from calcium to oxygen, so this reaction is an oxidation-reduction reaction.

+<u>O²</u><u>(</u><u>g</u><u>)</u><u>=</u><u>2</u><u>CaO</u><u>(</u><u>s</u><u>)</u>

Explanation:

we can conclude that in the reaction there is both reduction and oxidation.

6 0
3 years ago
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