The concentration of the sodium chloride would be 0.082 M
<h3>Stoichiometric calculations</h3>
From the equation of the reaction, the ratio of AgCl produced to NaCl required is 1:1.
Mole of 46.6 g AgCl produced = 46.6/143.32 = 0.325 moles
Equivalent mole of NaCl = 0.325 moles.
Molarity of 0.325 moles, 3.95 L NaCl = mole/volume = 0.325/3.95 = 0.082 M
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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The chemical could have more or less of a reaction to the other chemicals in the experiment
Answer:
Hydrochloride acid + Zinc = Zinc Chloride + Hydrogen
Explanation:
When Hydrochloride acid and Zinc react, it results in the formation of Zinc chloride and hydrogen.
<em>Hope I helped</em>
I think it's the last one
(and I'm so sorry if I'm wrong)